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Svetllana [295]
3 years ago
8

If in drawing your vector you are required to use a scale such that 25 grams represent 1 cm, and if your resultant vector measur

es 5 cm, how many grams should you add to your 50 gram weight hanger in order to represent it
Mathematics
1 answer:
Aleks04 [339]3 years ago
6 0

If we multiply the ratio

... 25 g : 1 cm

by 5, we get

... 125 g : 5 cm

The number on the left is 75 g more than 50 g.

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1. 6:8
gtnhenbr [62]
What are you asking? Are you asking to find an equal ratio for each?
8 0
3 years ago
Please answer only number seven.<br> Also, tell me the final answer and the process please
Sergeeva-Olga [200]
Left side is 22.
22 x 10 = 220
(20 - 6) x 12 = 168
6 x 20 = 120
220 + 168 + 120 = 508
Thank you very much.
7 0
3 years ago
A farmer can buy two types of plant​ food, mix A and mix B. Each cubic yard of mix A contains 35 pounds of phosphoric​ acid, 15
Nadusha1986 [10]

Answer:

The answer is below

Step-by-step explanation:

Given that the minimum monthly requirements are 840 pounds of phosphoric​ acid, hence:

35 pounds of phosphoric acid mix A + 14 pounds of phosphoric acid mix B ≥ 840 pounds of phosphoric​ acid

35x + 14y ≥ 840

The minimum monthly requirements are 540 pounds of nitrogen, hence:

15 pounds of nitrogen mix A + 18 pounds of nitrogen mix B ≥ 540 pounds of nitrogen

15x + 18y ≥ 540

The minimum monthly requirements are 768 pounds of potash, hence:

16 pounds of potash mix A + 64 pounds of potash mix B ≥ 768 pounds of potash

16x + 64y ≥ 768

Also, x ≥ 0 and y ≥0.

Therefore the equations are:

35x + 14y ≥ 840

15x + 18y ≥ 540

16x + 64y ≥ 768

x ≥ 0 and y ≥ 0

Plotting with geogebra gives the graph below.

The point are (0,60), (48,0), (18,15), (32,4)

7 0
3 years ago
Which of the following names the figure in the diagram below?
Greeley [361]

Answer:

pyramid

Step-by-step explanation:

4 0
3 years ago
PRACTICE ANOTHER A piece of wire 18 m long is cut into two pieces. One piece is bent into a square and the other is bent into an
sergejj [24]

Answer:

Step-by-step explanation:

We have the equations

4x + 3y = 18   where x = the side of the square and y = the side of the triangle

For the areas:

A = x^2 + √3y/2* y/2

A = x^2  + √3y^2/4

From the first equation x = (18 - 3y)/4

So substituting in the area equation:

A = [ (18 - 3y)/4]^2 + √3y^2/4

A = (18 - 3y)^2 / 16 + √3y^2/4

Now for maximum / minimum area the derivative = 0 so we have

A' = 1/16 * 2(18 - 3y) * -3 + 1/4 * 2√3 y = 0

-3/8 (18 - 3y) + √3 y /2 = 0

-27/4 + 9y/8 + √3y /2 = 0

-54 + 9y + 4√3y = 0

y = 54 / 15.93

= 3.39 metres

So x = (18-3(3.39) / 4 = 1.96.

This is a minimum value for x.

So the total length of wire the square  for minimum  total area is 4 * 1.96

= 7.84 m

There is no maximum area as the equation for the total area is a quadratic with a positive leading coefficient.

3 0
3 years ago
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