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Svetllana [295]

4 years ago

8

If in drawing your vector you are required to use a scale such that 25 grams represent 1 cm, and if your resultant vector measur

es 5 cm, how many grams should you add to your 50 gram weight hanger in order to represent it

1 answer:

Aleks04 [339]4 years ago

6 0

If we multiply the ratio

... 25 g : 1 cm

by 5, we get

... 125 g : 5 cm

The number on the left is 75 g more than 50 g.

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A rectangle has a perimeter of (12+8y). If one side of the rectangle is (4x-2y), write an expression of the other side.

ziro4ka [17]

P = 2(l+w)

substitute for P and l

12+8y = 2 (4x-2y+w)

distribute

12+8y = 8x -4y +2w

solve for w

subtract 8x from each side

12 +8y -8x = -4y+2w

add 4y to each side

12 +12 y -8x = 2w

divide by2

6 +6y-4x =w

the other side is 6+6y-4x

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3 years ago

Car leases generally allow only a certain number of miles to be driven. Myung’s lease included a charge of 25 cents per mile for

faust18 [17]

Answer:

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4 0

3 years ago

Lim x-0 3x²/(1-cos5x)

mylen [45]

The limit is presented in the following undefined form:

$\displaystyle \lim_{x\to 0}\dfrac{3x^2}{1-\cos(5x)} \to \dfrac{3\cdot 0^2}{1-\cos(5\cdot 0)} = \dfrac{0}{0}$

In cases like this, we can use de l'Hospital rule, which states that this limit, if it exists, is the same as the limit of the derivatives of numerator and denominator.

So, we switch

$\dfrac{f(x)}{g(x)}\to\dfrac{f'(x)}{g'(x)}$

The derivative of the numerator is

$\dfrac{d}{dx} 3x^2 = 6x$

Whereas the derivative of the denominator is

$\dfrac{d}{dx} (1-\cos(5x)) = 5\sin(5x)$

So, the new limit is

$\displaystyle \lim_{x\to 0}\dfrac{6x}{5\sin(5x)} \to \dfrac{6\cdot 0}{5\cdot 0} = \dfrac{0}{0}$

So, it would seem that we didn't solve anything, but indeed we have! Recall the limit

$\displaystyle \lim_{x\to 0} \dfrac{ax}{\sin(bx)} = \dfrac{a}{b}$

to conclude that the limit converges to \dfrac{6}{25} [/tex]

4 0

4 years ago

Read 2 more answers

Phil bought 700 shares of a company’s stock for $9.29/share. He pays a broker a commission of $18 to buy and sell stock. After o

Lelechka [254]

+ $0.61

Have a nice day.

5 0

4 years ago

The heights of women aged 20 to 29 is approximately Normal with mean 64 inches and standard deviation 2.7 inches. What proportio

natima [27]

20. 64. 2.7
+29 +49 58.6
------ ------ ---------
49. 113 60 .3

49+60.3+113=21.5

4 0

3 years ago