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VMariaS [17]
3 years ago
14

I have no clue what I’m doing.

Mathematics
2 answers:
motikmotik3 years ago
6 0
C. 102 should be correct
alukav5142 [94]3 years ago
4 0
The answer is C.) 102 .. multiply 120 by the 15% as a decimal sooo 120x.15 = 18. now subtract 18 from 120 and get 102 :)
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More properties of exponets<br> 2y² times 3xy³ over 3x²y^4
Greeley [361]
 the answer to the problem is 2y^3 3x3y4+4
6 0
3 years ago
2x1/8 trying get help it’s hard for me I have difficulty doing these problems
dmitriy555 [2]

Answer:

1/4

2 x 1/8 is also 1/8 + 1/8 and that is then 2/8 and after that when you simplify you get 1/4.

7 0
3 years ago
If it takes 100 g of sugar to make five cupcakes how many grams of sugar let me take to make 15 cupcakes
marissa [1.9K]

Answer:

300 g of sugar

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
Need help with thisss
frozen [14]

9514 1404 393

Answer:

  cos(x) = 0.6

Step-by-step explanation:

First, we need to find UQ.

  UQ = UP·cos(y°) = UP·√(1 -sin²(y°)) = (26 cm)√(1 -25/169) = (26 cm)(12/13)

  UQ = 24 cm

Then TQ is ...

  TQ = 1/3UQ = 1/3(24 cm) = 8 cm

And cos(x°) is ...

  cos(x°) = √(1 -sin²(x)) = √(1 -64/100)

  cos(x°) = 6/10 = 3/5

  cos(x°) = 3/5 = 0.6

7 0
3 years ago
For what values of t on the interval [0, 21 ]is the instantaneous velocity positive​ (the projectile moves​ upward)?
OLEGan [10]

Answer:

0 <=t<=21

Step-by-step explanation:

Projectile is Moving upwards on an interval of (0 to 21), if we plot Velocity vs Time and denote positive y-axis above 0 and negative y-axis below  0(for velocity), then from 0 to 21 t projectile is moving upwards and has positive velocity, when the projectile reaches the top of it's motion and returns back down to ground it's velocity is negative and is plotted below the y =0 (note that is for t > 21).

hence for the interval 0 <=t <=21 the instantaneous velocity is positive (Note, instantaneous velocity is also the derivative of the velocity or the slope ).

8 0
3 years ago
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