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VMariaS [17]
3 years ago
14

I have no clue what I’m doing.

Mathematics
2 answers:
motikmotik3 years ago
6 0
C. 102 should be correct
alukav5142 [94]3 years ago
4 0
The answer is C.) 102 .. multiply 120 by the 15% as a decimal sooo 120x.15 = 18. now subtract 18 from 120 and get 102 :)
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Define a function f on a set of real numbers as follows: f(x) = 3x − 1 x , for each real number x ≠ 0 Prove that f is one-to-one
dalvyx [7]

Answer with Step-by-step explanation:

We are given that

f(x)=\frac{3x-1}{x}

For each real number x\neq 0

To prove that f is one -to-one.

Proof:Let x_1 and x_2 be any nonzero real numbers such that

f(x_1)=f(x_2)

By using the definition of f to rewrite the left hand side of this equation

f(x_1)=\frac{3x_1-1}{x_1}

Then, by using the definition of f to rewrite the right hand side of this equation  of f(x_1)=f(x_2)

f(x_2)=\frac{3x_2-1}{x_2}

Equating the expression then we get

\frac{3x_1-1}{x_1}=\frac{3x_2-1}{x_2}

3x_1x_2-x_2=3x_2x_1-x_1

3x_1x_2-3x_1x_2+x_1=x_2

x_1=x_2

Therefore, f is one-to-one.

6 0
3 years ago
The sides of the rectangle are in the ratio of 4:7. If its length is 31.5 in., find the width, the perimeter, and the area of th
AveGali [126]
Let \ell the length and w the width. By the ratio of the sides:

\dfrac{w}{\ell}=\dfrac{4}{7}\Longrightarrow \dfrac{w}{31.5}=\dfrac{4}{7}\Longrightarrow w=\dfrac{4\cdot31.5}{7}\Longrightarrow \boxed{w=18~in.}

Now, we'll find the perimeter p. We'll use the formula below:

p=2(\ell+w)\\\\
p=2(31.5+18)\\\\
p=2\cdot49.5\\\\
\boxed{p=99~in.}

The area of a rectangle is S=w\cdot\ell. Then:

S=w\cdot\ell\\\\
S=18\cdot31.5\\\\
\boxed{S=567~in.^2}
8 0
3 years ago
Read 2 more answers
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Andrei [34K]

Answer:

Mean: 33.3

SD: 32.8

Step-by-step explanation:

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