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velikii [3]
3 years ago
15

Simplify i^5+i^6+ i^7+i^8 WILL GET 20 POINTS

Mathematics
1 answer:
Veronika [31]3 years ago
7 0
I^5 + i^6 + i^7 + i^8

i^11 + i^15

i^26

therefore your answer is:

i^26
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Solnce55 [7]

In Five month Jay should have $15,000  in his account has emergency fund

<h3>Given Data</h3>

Earnings per month = $4000

Monthly Expenses = $3000

Monthly Rent = $2000 part of monthly expenses

After deducting monthly expenses from Monthly earning we have

4000-3000 = $1000

<h3>Determining the 5-months Emergency Funds</h3>

Since we have a monthly expenses of $3000 a five month emergency fund will be

= 3000*5

= $15,000

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brainly.com/question/13420184

7 0
2 years ago
Find the product -2X²×4X²y²​
nydimaria [60]

Answer:

-8X^4y^2

Step-by-step explanation:

-2X² × 4X²y²​ = -8X^4y^2

edit to add:

first: multiply the coefficients together:

-2 x 4 = -8

second: add the exponents of X together (when you multiply exponents, you just add them together):

² & ² = ^4

and you have the answer:

-8X^4y^2

6 0
2 years ago
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In one month you had both a raise and a $250 bonus for exceeding your goals by 10%. Your old paycheck gross was $2,300, with a n
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411$ that's how much his raise was 
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3 years ago
What percent of $70,000 = $49,000​
vovikov84 [41]

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6 0
3 years ago
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Identify the center and radius from the equation of the circle given below. x^2+y^2+121-20y=-10x
Tcecarenko [31]

Answer:

Center: (-5,10)

Radius: 2

Step-by-step explanation:

The equation of the circle in center-radius form is:

(x-h)^2+(y-k)^2=r^2

Where the point (h,k)  is the center of the circle and "r" is the radius.

Subtract 121 from both sides of the equation:

x^2+y^2+121-20y-121=-10x-121\\x^2+y^2-20y=-10x-121

Add 10x to both sides:

x^2+y^2-20y+10x=-10x-121+10x\\x^2+y^2-20y+10x=-121

Make two groups for variable "x" and variable "y":

(x^2+10x)+(y^2-20y)=-121

Complete the square:

Add (\frac{10}{2})^2=5^2 inside the parentheses of "x".

Add  (\frac{20}{2})^2=10^2  inside the parentheses of "y".

Add 5^2 and 10^2 to the right side of the equation.

Then:

(x^2+10x+5^2)+(y^2-20y+10^2)=-121+5^2+10^2\\(x^2+10x+5^2)+(y^2-20y+10^2)=4

Rewriting, you get that the equation of the circle in center-radius form is:

 (x+5)^2+(y-10)^2=2^2

You can observe that the radius of the circle is:

r=2

And the center is:

(h,k)=(-5,10)

6 0
3 years ago
Read 2 more answers
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