All categories

2 years ago

Tina recorded the low temperatures for the last seven days. Here are her observations:

Mathematics

1 answer:

Whitepunk [10]2 years ago

4 0

59 because it is the weird one. 17 is no even one of the options

You might be interested in

A competitive knitter is knitting a circular place mat. The radius of the mat is given by the formula

Ilia_Sergeevich [38]

Answer: A. $A'(t)=\frac{4356\pi}{(t+11)^{3}}-\frac{527076\pi}{(t+11)^{5}}$

B. A'(5) = 1.76 cm/s

Step-by-step explanation: Rate of change measures the slope of a curve at a certain instant, therefore, rate is the derivative.

A. Area of a circle is given by

$A=\pi.r^{2}$

So to find the rate of the area:

$\frac{dA}{dt}=\frac{dA}{dr}.\frac{dr}{dt}$

$\frac{dA}{dr} =2.\pi.r$

Using $r(t)=3-\frac{363}{(t+11)^{2}}$

$\frac{dr}{dt}=\frac{726}{(t+11)^{3}}$

Then

$\frac{dA}{dt}=2.\pi.r.[\frac{726}{(t+11)^{3}}]$

$\frac{dA}{dt}=2.\pi.[3-\frac{363}{(t+11)^{2}}].\frac{726}{(t+11)^{3}}$

Multipying and simplifying:

$\frac{dA}{dt}=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}$

The rate at which the area is increasing is given by expression $A'(t)=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}$ .

B. At t = 5, rate is:

$A'(5)=\frac{4356\pi}{(5+11)^{3}} -\frac{527076\pi}{(5+11)^{5}}$

$A'(5)=\frac{4356\pi}{4096} -\frac{527076\pi}{1048576}$

$A'(5)=\frac{2408693760\pi}{4294967296}$

$A'(5)=1.76268$

At 5 seconds, the area is expanded at a rate of 1.76 cm/s.

5 0

2 years ago

find the equation of the line that is perpendicular to the given line and passes through the given point. CD; (-2,1). C cornet p

Studentka2010 [4]

Answer:

x -2y = -4

Step-by-step explanation:

The slope of the line between points C and D is ...

m = (y2 -y1)/(x2 -x1)

m = (7 -13)/(5 -2) = -6/3 = -2

The slope of the perpendicular line is the opposite reciprocal of this: -1/(-2) = 1/2. The point-slope equation of the desired line is ...

y -k = m(x -h) . . . . line with slope m through point (h, k)

y -1 = 1/2(x -(-2))

We can rearrange this to standard form.

2y -2 = x +2 . . . . . multiply by 2

-4 = x -2y . . . . . . . subtract 2y+2

x -2y = -4 . . . . . . standard form equation of the desired line

5 0

2 years ago

Find the lower quartile from the set of data below. 7,9, 9, 10, 14, 17, 20

KengaRu [80]

Answer:

7,9,9

Step-by-step explanation:

Because the numbers are lined up from least to greatest all you have to do is find the middle of all the numbers which is 10. So everything below ten is lower quartile. Everything above is upper quartile

5 0

2 years ago

Read 2 more answers

Find the value of 15625 × (-2) + (-15625) × 98

gregori [183]

Answer:

-1562500

Step-by-step explanation:

15625 × (-2) + (-15625) × 98 = -31250 + (-1531250)

= -31250 - 1531250

= -1562500

6 0

2 years ago

Read 2 more answers

What is the area of circle C when the radius is 0.4cm

Solnce55 [7]

I think it’s 0.5, sorry if it’s wrong

7 0

2 years ago