Jewelery maker has
24 jade beads
30 teak Beads
She has to make necklaces with each necklace having the same number of beads
So we need to find the highest common factor for both 24 and 30
The factors for both numbers are as follows
24 -1,2,3,4,6,8,12,24
30 - 1,2,3,5,6,10,15,30
The highest common factor for both is 6
The greatest number of necklaces she can make is 6
Number of jade beads - 24/6 = 4 jade beads
Number of teak beads - 30/6 = 5 teak beads
So each necklace will have 4 jade beads and 5 teak beads
Hello,
I suppose you mean using all those digits one time.
The sum of the digits is a multiple of 3.
Every number formed with those digits is a multiple of 3.
To be divisible by 2 , the number must end with an even digit (2,4,6)
So probability is 3/6=1/2
1 nickels =$0.05
1 dime= $0.1
let the number of nickels be x and that of dimes be y.
total number of coins is given by:
x+y=42
hence:
y=42-x.......i
total amount of cash will be:
0.05x+0.1y=3.30.........ii
substituting i in ii we get:
0.05x+0.1(42-x)=3.30
0.05x+4.2-0.1x=3.3
-0.05x=-0.9
x=-0.9/(-0.05)
x=18
hence the the number nickels is x=18, the number of dimes will be y=42-x=42-18=24
Answer:
In step 3
Step-by-step explanation:
Answer:
Whole numbers, repeating decimals, and decimals that never end
Step-by-step explanation:
