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Daniel [21]
3 years ago
10

Solve the solution to the equation -2x+1=9 step by step

Mathematics
2 answers:
Sergio039 [100]3 years ago
7 0
-2x+1=9\\
-2x=8\\
x=-4
Marizza181 [45]3 years ago
4 0
<u>-2x + 1 = 9</u>

Add 2x to each side of the equation:

1 = 2x + 9

Subtract 9 from each side:

-8 = 2x

Divide each side by 2 :

<u>-4 = x</u>
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Read 2 more answers
In 2002, Tim was twice as old as Sue. In 1997 the sum of their ages was 32. In what year will Sue's age be three-fourths Tim's a
xxMikexx [17]

Answer:

Year 2030.

Step-by-step explanation

In 1997, Let Tim's age = <em>X</em> years

In 1997, Let Sue's age = <em>Y</em> years

After 5 years in 2002, Tim's age = (<em>X+ 5) </em>years

After 5 years in 2002, Sue's age = <em>(Y + 5)</em> years

Now, According to question,

<em>X </em>+ <em>Y</em> = 32    (sum of their ages) .......(1)

<em>Y </em>= 32 -<em> X</em>

(X + 5) = 2 (Y + 5) .......(2)

Substituting the value of <em>Y</em> in (2)

<em>X </em>+ 5 = 2 (32 - <em>X </em>+ 5)

<em>X </em>+ 5 = 2 (37 - <em>X </em>)

<em>X </em>+ 5 = 74 - 2<em>X </em>

3<em>X </em>=<em> </em>69

<em>X </em>= 69/3 = 23

Now ∵<em> Y</em> = 32 - <em>X  </em>and<em> X = </em>23

∴ <em>Y</em> = 32 - 23 = 9

So, In 1997, Tim's age = 23 years and Sue's age = 9 years.

Let the year in which Sue's age will be three-fourth times of Tim's age be t.

Sue's age after<em> t </em>years = (9 +<em> t) </em>years.

Tim's age after<em> t</em> years = (23 + <em>t</em>) years

According to question,

(9 + t) = \frac{3}{4} \times(23 + t)

4 (9 + t) = 3 (23 + t)

36 + 4t = 69 + 3t

<em>4t - 3t = 69 - 36</em>

<em>t = 33</em>

The Year in which Sue's age will be three-fourth times of Tim's age is:

= (1997 + 33) = 2030.

4 0
3 years ago
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