The sum of 'k' and '7' is ' k + 7 '.
Five-sixths of that sum is ' (5/6)(k + 7) '.
The product of '6' and 'c' is '6c' .
"Five sixths of the sum of 'k' and '7' " minus the of '6'and 'c' is
<em> (5/6)(k + 7) - 6c</em>.
The average of 6 quiz scores, where
is the score of the last quiz, is

The student needs a minimum average of 86 to earn an A:

so the student needs a score of 91.
Answer:
I know it’s going to be -5 and -1.3 but I’m not sure about the zero I don’t know if you count zeros to but please let me know.
Answer: Third option is correct.
Step-by-step explanation:
Since we have given that
6, 6, 6, 7, 8, 8, 29
We will calculate the measures of central tendency:
1) Mode - the most occurring element in the data set.
So, Mode = 6
2) Median - the middle value of organised data set
So, Median = 7
3) Mean - the average of all data set
So, Mean = 
So, we can see that Mode and Median are giving the closest value to each other, whereas Mean is giving the farthest value as compared to rest.
Hence, Mean is the least appropriate for describing the given data set.
Thus, Third option is correct.