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3 years ago

Please help thank you

Mathematics

1 answer:

bekas [8.4K]3 years ago

3 0

Answer:

$40$

Step-by-step explanation:

$60 \div (6 \frac{1}{7} - \frac{1}{7}) \times 4 \\ \\ 60 \div ( \frac{43}{7} - \frac{1}{7} ) \times 4 \\ \\ 60 \div ( \frac{42}{7} ) \times 4 \\ \\ 60 \div 6 \times 4 \\ 10 \times 4 = 40$

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A bicycle tire is 28 inches in diameter. Approximately how far does the bicycle move forward each time the wheel goes around? (u

zhannawk [14.2K]

Answer: 88 inches

Step-by-step explanation:

A bicycle tire is 28 inches in diameter. approximately.

To find the distance traveled by the bicycle each time the wheel goes around we need to find the circumference of the tire.

The circumference of a circle: where d is the diameter of the circle.

Now, the circumference of the tire:

Hence, the distance traveled by the bicycle each time the wheel goes around =88 inches.

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3 years ago

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denis-greek [22]

Answer:

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Step-by-step explanation:

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3 years ago

3•(1+2)^2-4^2 evaluate

hammer [34]

Answer:

Step-by-step explanation:

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3 years ago

find the value of x2 values that separate the middle 90% from the rest of the distribution for 8 degrees of freedom

Anettt [7]

Answer:

With alpha 0.95 and 8 degrees of freedom χ²= 2.73

And with alpha 0.05 and 8 degrees of freedom χ²=15.51

Step-by-step explanation:

The significance level ∝ = 1- 0.9 = 0.1

But we need the area of the middle so we divide this significance level with 2

so that we get exactly the middle area .

Dividing 0.1/2= 0.05

So we will have two values for chi square

One with 0.9 + 0.05 = 0.95 alpha and one with 0.05 alpha . This is because the chi square is right tailed.

So with alpha 0.95 and 8 degrees of freedom χ²= 2.73

And with alpha 0.05 and 8 degrees of freedom χ²=15.51

This can be shown with a graph.

4 0

3 years ago

(a) Find a 90% confidence interval for the population mean price (per 100 pounds) that farmers in this region get for their wate

Anon25 [30]

Answer:

The margin of error (E) $=0.49$

Step-by-step explanation:

Given,

mean $\bar{x}=6.88$

standard deviation $\sigma=1.90$

sample size $n=41$

$90\% \quad \text{confidence interval}$

Critical value $=\frac{z_\alpha}{2}\quad \quad\quad[\because\;\alpha=1-\text{confidence interval}]$

$=1-0.90$

$\Rightarrow \alpha=0.1$

Critical value $=\frac{z_{0.1}}{2}$

$=z_{0.05}$

$=1.645$

The margin of error (E) $=\frac{z_\alpha}{2} \times\frac{\sigma}{\sqrt{n} }$

$=1.645\times\frac{1.90}{\sqrt{41} }$

$=0.49$

Hence, The margin of error (E) $=0.49$

Complete question is attached in below.

7 0

3 years ago

Please help thank you​

Please help thank you