What is the length and the width you need those to answer the question
First year: the depreciation is (35/100) x 20000 = £7000; now the value of the car is £20000 - £7000 = £13000;
Second year: the depreciation is (35/100) x 13000 = £4550; the current value of the car is £13000 - £4550 = £8450.
Answer:
C) 3(x+7)²
Step-by-step explanation:
Answer:
A) 2.6 mm Hg
Step-by-step explanation:
Margin of error = critical value × standard error
ME = CV × SE
n > 30, so we can approximate CV with a normal distribution. At P = 94%, CV = 1.88.
SE = σ / √n
SE = 13.5 / √92
SE = 1.41
So the margin of error is:
ME = 1.88 × 1.41
ME = 2.6
