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4 years ago

The perimeter of parallelogram WXYZ is 2 square roots of 26+ units

1 answer:

8 0

The formula for solving perimeter of a parallelogram is P=2(a+b) where "a" is for the altitude and "b" for the base. From the give figure, we can determine both a and b values as enumerated below,
a=5
b=4
We can solve for P as shown below,
P=2(5+4)
P=18 unit.
Therefore, the perimeter is equal to 18.

I hope this helps, have a great day, and God bless.
Brainliest is always appreciated :)

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What is the domain of the function y=2√x-6? 88AX<∞ O 0≤x<∞ 3≤x<∞ 6≤x<∞

Travka [436]

Answer:

If the x-6 is all under the sqrt, the last answer is right:

6<= x <= infinity

If only x is under the sqrt and - 6 is NOT under the sqrt, then:

0 <= x <= infinity is the correct answer.

Step-by-step explanation:

You can look at the equation and or graph to determine the domain of a function. The domain is all the x's that may go into the equation or all the x's on the graph of the function. Inside of a squareroot symbol the number inside there must be positive. While considering the equation, only x's that keep that inside positive can be used.

For sqrt(x-6), x has to be 6 or bigger.

For sqrt(x) - 6, x has to be 0 or bigger.

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2 years ago

From a point Q, the length of the tangent to a circle is 24 cm and the distance of Q from the centre is 25 cm find the radius of

Umnica [9.8K]

$\large\bold{{Question :}}$

From a point Q, the length of the tangent to a circle is 24 cm and the distance of Q from the centre is 25 cm find the radius of the circle.

$\large\bold\red{\underline{Solution :-}}$

Here, O is the center of the circle.

⟼ Given :

OQ = 25 cm
PQ = 24 cm

⟼ To Find : We have to find the radius OP.

Since QP is tangent, OP perpendicular to QP.

(Since, Tangent is Perpendicular to Radius ⠀⠀⠀⠀⠀⠀⠀at the point of contact)

So, ∠OPQ=90°

⟼ By Applying Pythagoras Theorem :

OP² + RQ² = OQ²

OP² + (24)² = (25)²

OP² = 625 - 576

OP² = 49

OP = √49

OP = 7 cm

Hence, The Radius is 7 cm

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<h3>-MissAbhi</h3>

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Step-by-step explanation:

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