Question

Y1=4(5x-1), y2-=5x+1 and y1 is 344 more than 2 times y2

Answer 1

 $y_1=4(5^x-1)$ and $y_2=5^x+1$

$y_1=344+2y_2$
$y_1=344+2(5^x+1)$
$4(5^x-1) = 344 + 2(5^x+1)$
$(4)(5^x)-4=344+2(5^x)+2$
$4(5^x)-2(5^x)=344+2+4$
$2(5^x)=350$
$5^x= \frac{350}{2}$
$5^x=175$
$log(5^x)=log(175)$
$x(log(5))=log(175)$
$x= \frac{log175}{log5}$
$x=3.21$ (rounded to two decimal places)