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Harrizon [31]
3 years ago
7

Can someone solve this for me

Mathematics
1 answer:
Alecsey [184]3 years ago
3 0

Answer:

12 {y}^{9}  - 6 {y}^{5}  + 4 {y}^{2}  + 21

Step-by-step explanation:

divide each term by 2y^3

Multiply through by the least common denominator.

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How do I turn this equation into standard form?<br> 8x=-5y+3
NARA [144]

Answer:

Step-by-step explanation:

To write a linear equation in standard form, move each variable term to the left side of the equation and simplify.

Ax+By=C

Since x is on the right side of the equation, switch the sides so it is on the left side of the equation.

8x−3=y

Move y to the left side of the equation because it contains a variable.

8x−3−y=0

Move 3 to the right side of the equation because it does not contain a variable.

8x−y=3

8 0
2 years ago
What is an equation of the line that passes through the points (4,1) and (8,-3)?
Rus_ich [418]

Answer:

y=-x+5

Step-by-step explanation:

(4,1)

(8,-3)

1)a slope of a line is (y2-y1)/(x2-x1)

  so (-3-1)/(8-4)

  -4/4=>m=-1

2)to find y-int replace any points in the equation by x and y

so    1=-1(4)+b

        1=-4+b

        1+4=b

so b= 5

therefore the equation is  y=-x+5   so d

8 0
3 years ago
Blue is sus vote him out<br><br>#BlueIsImposter<br>or #Idiot
taurus [48]
Blue was not the imposter.
8 0
2 years ago
Santos is a lifeguard and spots a drowning child 50 meters along the shore and 60 meters from the shore to the child. Santos run
Amanda [17]

Answer:

Santos should run approximately 36.145 meters along the shore

Step-by-step explanation:

The given parameters are;

The distance along the shore of the child = 50 meters

The distance from the shore of the child = 60 meters

The rate at which Santos can run = 4 m/s

The rate he can swim = 0.9 m/s

Let 'x' represent the distance he runs along the shore

We have;

The time he spends running on the shore, t₁ = x/4

The time he spends swimming, t₂ = (√(60² + (50 - x)²)/0.9

The total time, T = t₁ + t₂ = x/4 + (√(60² + (50 - x)²)/0.9

To find the maximum, we have;

dT/dx = 0 = d(x/4 + (√(60² + (50 - x)²)/0.9)/dx = 1/4 - (50 - x)/(0.9·(√(60² + (50 - x)²) = 0

1/4 - (50 - x)/(0.9·(√(60² + (50 - x)²) = 0

Simplifying using a graphing calculator gives;

\dfrac{x - 2000}{9} = \sqrt{x^2-100\cdot x+6,100}

1519·x² - 151900·x + 3505900 = 0

x = (151900 ± √((-151900)² - 4×1519×3505900))/(2 × 1519)

x ≈ 63.86 m or x ≈ 36.145 m

We note that the distance from a point x = 63.83 meters and 36.145 meters from where Santos spots the girl to the location of the girl are the same

Therefore, Santos should run approximately 36.145 meters along the shore before jumping into to the water in order to save the child

7 0
2 years ago
Pls answer this! I need to pass!
KengaRu [80]

Answer:

b

Step-by-step explanation:

6 0
3 years ago
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