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3 years ago

7

Brittany has 18 trading cards. Anthony has t more trading cards than Brittany. Write an expression that shows how many trading c

ards Anthony has.

1 answer:

igomit [66]3 years ago

5 0

Answer:

a = b + t

or

a = 18 + t

Step-by-step explanation:

This can be put into a simple expression:

Let a be Anthony's cards and b be Brittany's cards:

A = b + t

or

A = 18 + t

Hope this helps!

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. Given ????(5, −4) and T(−8,12):

damaskus [11]

Answer:

a) $y=\dfrac{13x}{16}-\dfrac{129}{16}$

b) $y = \dfrac{13x}{16}+ \dfrac{37}{2}$

Step-by-step explanation:

Given two points: $S(5,-4)$ and $T(-8,12)$

Since in both questions,a and b, we're asked to find lines that are perpendicular to ST. So, we'll do that first!

Perpendicular to ST:

the equation of any line is given by: $y = mx + c$ where, m is the slope(also known as gradient), and c is the y-intercept.

to find the perpendicular of ST <u>we first need to find the gradient of ST, using the gradient formula.</u>

$m = \dfrac{y_2 - y_1}{x_2 - x_1}$

the coordinates of S and T can be used here. (it doesn't matter if you choose them in any order: S can be either x_1 and y_1 or x_2 and y_2)

$m = \dfrac{12 - (-4)}{(-8) - 5}$

$m = \dfrac{-16}{13}$

to find the perpendicular of this gradient: we'll use:

$m_1m_2=-1$

both $m_1$ and $m_2$ denote slopes that are perpendicular to each other. So if $m_1 = \dfrac{12 - (-4)}{(-8) - 5}$ , then we can solve for $m_2$ for the slop of ther perpendicular!

$\left(\dfrac{-16}{13}\right)m_2=-1$

$m_2=\dfrac{13}{16}$ :: this is the slope of the perpendicular

a) Line through S and Perpendicular to ST

to find any equation of the line all we need is the slope $m$ and the points $(x,y)$ . And plug into the equation: $(y - y_1) = m(x-x_1)$

side note: you can also use the $y = mx + c$ to find the equation of the line. both of these equations are the same. but I prefer (and also recommend) to use the former equation since the value of 'c' comes out on its own.

$(y - y_1) = m(x-x_1)$

we have the slope of the perpendicular to ST i.e $m=\dfrac{13}{16}$

and the line should pass throught S as well, i.e $(5,-4)$ . Plugging all these values in the equation we'll get.

$(y - (-4)) = \dfrac{13}{16}(x-5)$

$y +4 = \dfrac{13x}{16}-\dfrac{65}{16}$

$y = \dfrac{13x}{16}-\dfrac{65}{16}-4$

$y=\dfrac{13x}{16}-\dfrac{129}{16}$

this is the equation of the line that is perpendicular to ST and passes through S

a) Line through T and Perpendicular to ST

we'll do the same thing for $T(-8,12)$

$(y - y_1) = m(x-x_1)$

$(y -12) = \dfrac{13}{16}(x+8)$

$y = \dfrac{13x}{16}+ \dfrac{104}{16}+12$

$y = \dfrac{13x}{16}+ \dfrac{37}{2}$

this is the equation of the line that is perpendicular to ST and passes through T

7 0

3 years ago

Solve for the compound inequality 6b < 42 or 4b + 12 > 8.

Anuta_ua [19.1K]

Answer:

-1<b<7, or i suppose b.

Step-by-step explanation:

6b<42

b<7

4b+12>8

4b>-4

b>-1

6 0

3 years ago

You invest $2,500 in an account that grows 5% each year. what will be your investment amount after 6 years?

lesantik [10]

Answer: b. $3,374.65

Step-by-step explanation:

The exponential equation of growth (continuously) is given by :-

$y=Ae^{rx}$ , where A is the initial amount, r is the rate of growth ( in decimal) and x is the time period.

Given : You invest $2,500 in an account that grows 5% each year.

i.e. A= $2,500 and r= 5%=0.05

Then, the equation model this situation will be :-

$y=2500e^{0.05x}=2500(1.05)^x$

Now, At x= 6

$y=2500e^{0.05\times6}\\\\\Rightarrow\ y=2500e^{0.3}=3374.64701894\approx3374.65$

Hence, the investment amount after 6 years will be $3,374.65.

4 0

3 years ago

Which sequence of transformations will result in similar, but not congruent, figures?

Rudik [331]

D.dilation changes the size is your answer. Hope this helps!

8 0

3 years ago

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Hudson runs 4 miles per day. What is the relationship between the number of days and how many miles he has run

Citrus2011 [14]

Answer:

Running 3 miles a day, paired with a healthy diet and lifestyle habits, can help you burn excess body fat. ... The key to losing weight is establishing a caloric deficit, or burning more calories than you take in, and running is great for burning calories.May 28, 2019

Step-by-step explanation:

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3 years ago