All categories

3 years ago

Helppp please i need it

Mathematics

2 answers:

Ipatiy [6.2K]3 years ago

8 0

That = (f(2) - f(-1) / 2 - -1 = 8 - 5 / 3 = 1 answer

bixtya [17]3 years ago

3 0

The change in the independent variable from -1 to 2 is 3.
The corresponding change in the dep't var is f(3) - f(-1), which can be found as follows:

(3)^4 - 4x - [(-1)^4 - 4(-1)] = 8 - 5 = 3

Then the ave. r. of c. of the given function on the given interval
is 3/3, or 1.

You might be interested in

Please help me solve the screenshot below.

Harrizon [31]

Answer:

The arrangement of the given equation in the slope - intercept form are

$y=-x+4$
$y=2x-5$

Step-by-step explanation:

Given:

x + y = 4 and

y - 2x = -5

Slope - intercept form :

$y=mx+c$

Where,

m is the slope of the line.

c is the y-intercept.

When two points are given say ( x1 , y1 ) and ( x2 , y2) we can remove slope by

Slope,

$m=\frac{y_{2}- y_{1}}{x_{2}- x_{1}}$

Intercepts: Where the line cut X axis called X- intercept and where cut Y axis is called Y- intercept.

So, the Slope -intercept form of

x + y = 4 is $y=-x+4$

and

y - 2x = -5 is $y=2x-5$

3 0

4 years ago

on a recent hike through riverbend park antoinette traveled 2/3 mile in 1/3 hour . Which unit rate describes antoinettes speed i

My name is Ann [436]

Answer:

Her speed is of 2 miles per hour.

Step-by-step explanation:

Velocity:

The velocity is given by the following formula:

$v = \frac{d}{t}$

In which v is the velocity, d is the distance and t is the time.

2/3 mile in 1/3 hour .

This means that $d = \frac{2}{3}, t = \frac{1}{3}$

Which unit rate describes antoinettes speed in miles per hour?

This is v. So

$v = \frac{d}{t} = \frac{\frac{2}{3}}{\frac{1}{3}} = \frac{2}{3}*\frac{3}{1} = 2$

Her speed is of 2 miles per hour.

5 0

3 years ago

It is known that there only is 1% chance of getting a disease. a test is being devised to detect the disease. the probability th

Cerrena [4.2K]

Suppose $D$ is the event that a given patient has the disease, and $P$ is the event of a positive test result.

We're given that

$\mathbb P(D)=0.01$
$\mathbb P(P\mid D)=0.98$
$\mathbb P(P^C\mid D^C)=0.95$

where $A^C$ denotes the complement of an event $A$ .

a. We want to find $\mathbb P(P^C)$ . By the law of total probability, we have

$\mathbb P(P^C)=\mathbb P(P^C\cap D)+\mathbb P(P^C\cap D^C)$

That is, in order for $P^C$ to occur, it must be the case that either $D$ also occurs, or $D^C$ does. Then from the definition of conditional probability we expand this as

$\mathbb P(P^C)=\mathbb P(D)\mathbb P(P^C\mid D)+\mathbb P(D^C)\mathbb P(P^C\mid D^C)$

so we get

$\mathbb P(P^C)=0.01\cdot0.02+0.99\cdot0.95=0.9407$

b. We want to find $\mathbb P(D\mid P)$ . Now, we can use Bayes' rule, but if you're like me and you find the formula a bit harder to remember, we can easily derive it.

By the definition of conditional probability,

$\mathbb P(D\mid P)=\dfrac{\mathbb P(D\cap P)}{\mathbb P(P)}$

We have the probabilities of $P$ / $P^C$ occurring given that $D$ / $D^C$ occurs, but not vice versa. However, we can expand the probability in the numerator to get a probability in terms of $P$ being conditioned on $D$ :

$\mathbb P(D\cap P)=\mathbb P(D)\mathbb P(P\mid D)$

Meanwhile, the law of total probability lets us rewrite the denominator as

$\mathbb P(P)=\mathbb P(P\cap D)+\mathbb P(P\cap D^C)$

or in terms of conditional probabilities,

$\mathbb P(P)=\mathbb P(D)\mathbb P(P\mid D)+\mathbb P(D^C)\mathbb P(P\mid D^C)$

so that

$\mathbb P(D\mid P)=\dfrac{\mathbb P(D)\mathbb P(P\mid D)}{\mathbb P(D)\mathbb P(P\mid D)+\mathbb P(D^C)\mathbb P(P\mid D^C)}$

which is exactly what Bayes' rule states. So we get

$\mathbb P(D\mid P)=\dfrac{0.01\cdot0.98}{0.01\cdot0.98+0.99\cdot0.05}\approx0.1653$

6 0

3 years ago

I need help please.

Zarrin [17]

Answer:

i think this is it

Step-by-step explanation:

the answer i got is just 55

3 0

4 years ago

Solve each equation. <br> 4.) 0= -5n-2n5<br> 5.) 6 r − 1 + 6 r = 11 <br> 6.) r + 11 + 8 r = 29

neonofarm [45]

Answer:

5) 6r-1+6r=11

Step-by-step explanation:

if you add everything up you get that

5 0

3 years ago