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n200080 [17]
3 years ago
15

Write a rule for the linear function in the table.

Mathematics
1 answer:
JulijaS [17]3 years ago
6 0

Answer:

I guess that you want to know the transformations:

We start with:

f(x) = y = 4*x + 3

a)the transformed function is:

f(x) = y = -4*x - 3

So the sign changed.

This means that we go from (x, y) to (x, - y)

This is a reflection over the x-axis which changes the sin of the y component.

b) Now we go to f(x) = 4*x + 3

So the coefficient in the leading term changed.

This is a horizontal contraction:

A horizontal contraction of factor K for the function g(x) is: g(K*x)

In our case, we have:

f(K*x) = 4*(k*x) + 3 = x + 3

4*k*x = x

4*k = 1

k = 1/4

Then the transformation is an horizontal contraction of scale factor 1/4.

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PLEASE SOMEONE HELP ME PLEASE :(
creativ13 [48]

Answer:

1 and 5= corresponding angles.

4 and 2=vertical opposite angle

3 and 6=co interior angle.

5 and 8=linear pair.

5 and 3= alternate interior angle

2 and 8=alternate exterior angle.

3 0
3 years ago
Read 2 more answers
Consider the function. f(x)= -2/3x-24 Which conclusions can be drawn about f–1(x)? Select two options. f–1(x) has a slope of -2/
disa [49]

Answer:

(D) f^{-1}{(x$) has an x-intercept of (-36, 0).

(E)f^{-1}{(x) has a range of all real numbers.

Step-by-step explanation:

Given the function: f(x)= -\dfrac23x-24

f(x)+24= -\dfrac23x\\$Multiply both sides by $  -\dfrac32\\x=-\dfrac32(f(x)+24)\\f^{-1}(x)=-\dfrac32f(x)-36

When y=f(x)=0

f^{-1}(x)=-\dfrac32(0)-36\\f^{-1}(x)=-36

Therefore, f^{-1}(x)$ has a x-intercept of -36

Also, f^{-1}(x) has a range of all real numbers.

Therefore, Options D and E are correct.

5 0
3 years ago
How many 1 2/3 are in 1 1/6​
Flura [38]

Answer:

7/10

Step-by-step explanation:

To find how many of x are y, you solve <em>y/x</em>.

With our numbers, we have <em>7/6 ÷ 5/3</em>.

We can turn that into <em>7/6 × 3/5</em> = <em>21/30</em> = 7/10.

5 0
3 years ago
Chapter 1: Quadrati
Bad White [126]

Answer:

mid point of AB (0.5 , 0)

Step-by-step explanation:

2x + 5y = 1      2x = 1 - 5y

y = 2xy+ 5 = (1 - 5y)*y + 5 = y - 5y² + 5

y-y = y - 5y² + 5 - y = - 5y² + 5

0 = - 5y² + 5

5y² = 5

y² = 1

y = 1 or y = -1

if y = 1       x = 1/2 (1 - 5) = -2   .... point A (-2 , 1)

if y = -1      x = 1/2 (1 + 5) = 3   ..... point B (3 , -1)

mid point of AB (x' , y') :  x' = 1/2 (x₁ + x₂) = 1/2 (-2 + 3) = 1/2

                                        y' =  1/2 (y₁ + y₂) = 1/2 (-1 + 1) = 0    

8 0
3 years ago
How do I solve this?
EastWind [94]

Answer:

i think that you have to divide each fraction, andmaybe find the other fractions

Step-by-step explanation:

5 0
3 years ago
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