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Murrr4er [49]
3 years ago
11

Find the equation of the line that passes through (3,-2) and whose m=1/2

Mathematics
1 answer:
Oxana [17]3 years ago
8 0

y=m x+c

If m=\frac{1}{2}

Then:

y=\frac{1}{2} x+c

Sub in the coordinates given to you:

-2=\frac{1}{2} *3+c

Now:

\frac{1}{2}*3=1.5

Move 1.5 to the other side of the equation and flip the sign.

-2-1.5=c

Therefore, c = -3.5.

Replace in the formula (y=mx+c):

y=\frac{1}{2}x-3.5

There is your answer.

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Suppose that bugs are present in 1% of all computer programs. A computer de-bugging program detects an actual bug with probabili
lawyer [7]

Answer:

(i) The probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

Step-by-step explanation:

Denote the events as follows:

<em>B</em> = bugs are present in a computer program.

<em>D</em> = a de-bugging program detects the bug.

The information provided is:

P(B) =0.01\\P(D|B)=0.99\\P(D|B^{c})=0.02

(i)

The probability that there is a bug in the program given that the de-bugging program has detected the bug is, P (B | D).

The Bayes' theorem states that the conditional probability of an event <em>E </em>given that another event <em>X</em> has already occurred is:

P(E|X)=\frac{P(X|E)P(E)}{P(X|E)P(E)+P(X|E^{c})P(E^{c})}

Use the Bayes' theorem to compute the value of P (B | D) as follows:

P(B|D)=\frac{P(D|B)P(B)}{P(D|B)P(B)+P(D|B^{c})P(B^{c})}=\frac{(0.99\times 0.01)}{(0.99\times 0.01)+(0.02\times (1-0.01))}=0.3333

Thus, the probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii)

The probability that a bug is actually present given that the de-bugging program claims that bug is present is:

P (B|D) = 0.3333

Now it is provided that two tests are performed on the program A.

Both the test are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is:

P (Bugs are actually present | Detects on both test) = P (B|D) × P (B|D)

                                                                                     =0.3333\times 0.3333\\=0.11108889\\\approx 0.1111

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii)

Now it is provided that three tests are performed on the program A.

All the three tests are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is:

P (Bugs are actually present | Detects on all 3 test)

= P (B|D) × P (B|D) × P (B|D)

=0.3333\times 0.3333\times 0.3333\\=0.037025927037\\\approx 0.037

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

4 0
3 years ago
Plzzzz due in a few mins help
Eduardwww [97]

Answer:

equation: 4x+6=9

x=0.75

Step-by-step explanation:

4x+6=9

subtract 6 from both sides

4x+6-6=9-6

4x=3

divide by 4 on both sides

4x÷4=3÷4

x=0.75

I hope this is good enough:

6 0
2 years ago
Read 2 more answers
Which is true about the polynomial
kupik [55]
Binomial with degree of 3
6 0
3 years ago
Read 2 more answers
Which term best describes the geometric figure?
o-na [289]

Answer:Line Point Ray Segment

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A square has an area of 36 cm. how long is one of its sides?
Leokris [45]
The correct answer would be 6.

To figure this out, you take the square root of 36 since area of a square is side x side.
8 0
3 years ago
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