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patriot [66]
3 years ago
10

How would I do number 5?

Mathematics
1 answer:
sukhopar [10]3 years ago
3 0
N - 5 ≥ -2

5 - 5 ≥ -2 

5 - 5 = 0

n = 5

5 - 5 ≥ -2

5 - 5 = 0

(0 ≥ -2)
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babymother [125]

Answer:

m∠RPQ = 8°

Step-by-step explanation:

m∠QRS = 4x - 15

m∠RPQ = x + 1

m∠PQR = x - 2

m∠QRS is exterior angle and m∠RPQ and m∠PQr are opposite interior angles to m∠QRS

m∠QRS = m∠RPQ + m∠PQR      {Exterior angle property of triangle}

4x - 15 = x +1 + x - 2

4x - 15 = x + x + 1-2          {Combine like terms}

4x - 15 = 2x - 1        {Subtract 2x from both sides}

4x - 2x - 15 = - 1

2x - 15 = - 1                  {Add 15 to both sides}

2x = -1 + 15

2x = 14          {Divide both sides by 2}

x = 14/2

x = 7

m∠RPQ = x + 1 = 7 + 1 = 8°

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