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3 years ago

What is 2x+2x-4+2x+4x

2 answers:

8 0

Hey there!
This question is about finding and combining like terms.

Like terms are essentially terms with the same variable. This means that out like terms are 2x, 2x, 2x, and 4x.

Therefore, we have:
x(2+2+2+4) = x(10) = 10x
Another way to do this is to just add the coefficients to get 10x.

Remeber we're subtracting four too, so our answer is:

10x - 4

Hope this helps!

Alchen [17]3 years ago

3 0

To solve this question, simply add the terms that are the same together, in this case you would add 2x together and 4x’s.

Keep the constant 4 separate.

10x - 4, should be the answer.

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Write an expression that can be used to multiply 6x198 mentally

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What is 8y=48 what is the answer to the problem

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48 divided by 8 equals 6

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Patel squeezed oranges so that his family could have fresh-squeezed juice for breakfast. He squeezed StartFraction 4 over 17 End

IgorC [24]

Answer:

$\approx \frac{11}{40}$

Step-by-step explanation:

Juice squeezed from first orange = $\frac{4}{17}$ = 0.235

Juice squeezed from second orange = $\frac{3}{10}$ = 0.3

Juice squeezed from third orange = $\frac{9}{20}$ = 0.45

Juice squeezed from fourth orange = $\frac{3}{11}$ = 0.27

Juice squeezed from fifth orange = $\frac{7}{15}$ = 0.47

Total juice squeezed from all the five oranges = 0.235 + 0.3 + 0.45 + 0.27 + 0.47 = 1.725

Total juice to be squeezed = 2 cups

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3 years ago

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1. What is the solution to this equation?<br> 2 x + 10 = 28

Colt1911 [192]

Answer:

Step-by-step explanation:

2x=28-10

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The taxi and takeoff time for commercial jets is a random variable x with a mean of 8.9 minutes and a standard deviation of 2.9

Eva8 [605]

Answer:

a) 0.2981 = 29.81% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

b) 0.999 = 99.9% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes

c) 0.2971 = 29.71% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 8.9 minutes and a standard deviation of 2.9 minutes.

This means that $\mu = 8.9, \sigma = 2.9$

Sample of 37:

This means that $n = 37, s = \frac{2.9}{\sqrt{37}}$

(a) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes?

320/37 = 8.64865

Sample mean below 8.64865, which is the p-value of Z when X = 8.64865. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{8.64865 - 8.9}{\frac{2.9}{\sqrt{37}}}$

$Z = -0.53$

$Z = -0.53$ has a p-value of 0.2981

0.2981 = 29.81% probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.

(b) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes?

275/37 = 7.4324

Sample mean above 7.4324, which is 1 subtracted by the p-value of Z when X = 7.4324. So

$Z = \frac{X - \mu}{s}$

$Z = \frac{7.4324 - 8.9}{\frac{2.9}{\sqrt{37}}}$

$Z = -3.08$

$Z = -3.08$ has a p-value of 0.001

1 - 0.001 = 0.999

0.999 = 99.9% probability that for 37 jets on a given runway, total taxi and takeoff time will be more than 275 minutes.

(c) What is the probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes?

Sample mean between 7.4324 minutes and 8.64865 minutes, which is the p-value of Z when X = 8.64865 subtracted by the p-value of Z when X = 7.4324. So

0.2981 - 0.0010 = 0.2971

0.2971 = 29.71% probability that for 37 jets on a given runway, total taxi and takeoff time will be between 275 and 320 minutes

7 0

3 years ago