Answer:
4
Step-by-step explanation:
The question is not clear. You have indicated the original function as 12sin(0) - 9sin²(0)
If so, the solution is trivial. At 0, sin(0) is 0 so the solution is 0
However, I will assume you meant the angle to be 
rather than 0 which makes sense and proceed accordingly
We can find the maximum or minimum of any function by finding the first derivate and setting it equal to 0
The original function is
Taking the first derivative of this with respect to and setting it equal to 0 lets us solve for the maximum (or minimum) value
The first derivative of 
w.r.t is
And setting this = 0 gives
Eliminating 
on both sides and solving for 
gives us
Plugging this value of into the original equation gives us
This is the maximum value that the function can acquire. The attached graph shows this as correct
78×.33=25.74 busses are new
25.74+15=40.74 new busses
78+15=93 total busses
40.74/78=0.5223076923= 52% will be new with the new 15 busses
X can be any real number
As long as it is to the power of 0, it will equal one. And because 6^0 = 1, 1^x can be any positive number, and it will still give you one.
As stated by WojtekR, even negative numbers can get 1
x = - 5
(6^0)^-5 = 1^-5 = 1/1 = 1
~ Thanks @WojtekR
Answer: a) P = 0.5, b) P = 0.07
Step-by-step explanation:
Hi!
Lets call X₁ the time at which you arrive, and X₂ the time at which Bob arrives. Both are random variables with uniform density in the interval [0, 60] (in minutes). Their joint distribuition is uniform over the square in the image, with value P = 1/(60*60) = 1/3600.
a) For you to get more cake than Bob, you should arrive earlier. This event is A = { X₁ < X₂ }, the shaded triangle in the figure.The area of this event (set) is half the total area of the square, so P(A) = 0.5.
It makes sense, beacuse its equally probable for you or Bob to arrive earlier, as both have uniform density over the time interval.
b) In this case you arrive later than Bob, but less than 5 minutes later. So the event is B = { X₂ < X₁ < (X₂ + 5) } . This is the gray shaded area in b) part of the image. Its area is the difference two triangles (half square - blue triangle), then the probability is:
