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Tems11 [23]
3 years ago
5

Four of the test subjects are randomly selected without​ replacement, and they all had true negative test results

Mathematics
1 answer:
8090 [49]3 years ago
5 0
<span>(24/98) * (23/97) * (22/96) * (21/95) </span>
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A bus has less than 42 seats. If 36 seats are already occupied, write an
Fudgin [204]

Answer:

B

Step-by-step explanation:

A x - 36 <42 is wrong because its saying how many can be added

B x +36 < 42 this one is most likely correct because its displays x as how many can be added

C x - 36 > 42 this is wrong because the bus has less than 42 seats

D x + 36 >57 like i said cant be over 42

8 0
3 years ago
Help please and thank you
iren [92.7K]
What do you need what is the question
8 0
3 years ago
Question Category: Solving Quadratic Equations by Factoring Select the correct answer. Find the solution(s) for x in the equatio
Novay_Z [31]

Answer: x = 4; x = 5

Step-by-step explanation:

The directions specify to solve by factoring

x^2 - 9x + 20 = 0

To factor, find two numbers that add to -9 and multiply to 20

-5 and -4 work

-5 + (-4) = -9

-5 * -4 = 20

(x - 4)(x - 5) = 0

x = 4, x =5

6 0
3 years ago
What is (0,1) and (4,2) in slope intercept form
emmasim [6.3K]

Answer:

y = 0.25x+1

Step-by-step explanation:

Y= mx+b

m= 0.25

b= 1

hope this helps

6 0
2 years ago
A motorist left town X at 08 00 for town Y situated 120km away, travelling at a constant speed of v km/hr, so as to arrive at Y
mote1985 [20]
<span>v = 45 km/hr u = 72 km/hr Can't sketch the graph, but can describe it. The Y-axis will be the distance. At the origin it will be 0, and at the highest point it will have the value of 120. The X-axis will be time in minutes. At the origin it will be 0 and at the rightmost point, it will be 160. The graph will consist of 3 line segments. They are 1. A segment from (0,0) to (80,60) 2. A segment from (80,60) to (110,60) 3. A segment from (110,60) to (160,120) The motorist originally intended on driving for 2 2/3 hours to travel 120 km. So divide the distance by the time to get the original intended speed. 120 km / 8/3 = 120 km * 3/8 = 360/8 = 45 km/hr After traveling for 80 minutes (half of the original time allowed), the motorist should be half of the way to the destination, or 120/2 = 60km. Let's verify that. 45 * 4/3 = 180/3 = 60 km. So we have a good cross check that our initial speed was correct. v = 45 km/hr Now having spent 30 minutes fixing the problem, out motorist now has 160-80-30 = 50 minutes available to travel 60 km. So let's divide the distance by time: 60 / 5/6 = 60 * 6/5 = 360/5 = 72 km/hr So the 2nd leg of the trip was at a speed of 72 km/hr</span>
6 0
3 years ago
Read 2 more answers
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