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nadya68 [22]
4 years ago
12

What is the volume of a right circular cylinder with a base diameter of 6 m and a height of 5 m?

Mathematics
2 answers:
marta [7]4 years ago
7 0

Answer:

The volume of the right circular cylinder is 45π m³

Step-by-step explanation:

To solve this, we will follow the steps below;

We will simply use the formula;

v =  π r² h

Where v is the volume of the cylinder

π  is a constant

r is the radius

h is the height

From the question given;

diameter = 6 m but radius is half diameter, this implies radius =  d/2 =6/2 =  3 m

radius = 3 m

height = 5 m

We can now proceed to insert our values into the formula;

v =  π r² h

     =π × 3² × 5

      =π × 9 × 5

       =45π

Therefore the volume of the right circular cylinder is 45π m³

DaniilM [7]4 years ago
4 0

Answer:

141.3 cubic inches

Step-by-step explanation:

The volume of a cylinder is found using the volume formula V=\pi r^2h.

The radius is half the diameter 6 which is 3.

Substitute h=5 and r = 3.

V = \pi r^2h\\V = \pi (3^2)(5)\\V=\pi *9*5\\V = 45\pi \\V= 141.3

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Adam says that the number 4 has four factors. Explain why this statement is incorrect.
gulaghasi [49]

The Factors of Number '4' are 1 , 2 , 4

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If the mass of two objects is increased, what is the effect on the force between them?
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A

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So the answer is A

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3 years ago
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Altitudes $\overline{ax}$ and $\overline{by}$ of acute triangle $abc$ intersect at $h$. if $\angle ahb = 132^\circ$, then what i
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Answer: 48 degrees

-------------------------------------------------------

See the attached image for a visual of the problem and answer.

Based on the diagram, we have angle AHB = 132 degrees (given) equal in measure to angle XHY since these two angles are vertical angles. 

Angles HYC and HXC are right angles due to the nature of AX and BY being altitudes. Recall that altitudes are segments that go from one vertex to the opposite side and they are perpendicular to the opposite side.

Focus on quadrilateral HXCY. So far, we know that...
Angle XHY = 132 degrees
Angle HYC = 90 degrees
Angle HXC = 90 degrees

The angle we want to find is angle ACB, which is the same as angle YCX. This angle is the missing angle of the quadrilateral HXCY.

For any quadrilateral, the four angles must add to 360 degrees. 

(angle XHY) + (angle HYC) + (angle HXC) + (angle YCX) = 360
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angle YCX = 48 degrees

Since angle ACB is the same as angle YCX, we can say
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