2 years ago

Given the function f(x) = x2 and k = –1, which of the following represents a function opening downward?

1 answer:

5 0

f(x) = ax2+bx+c, is quadratic equation
function opening downward if the a<0,
kf(x) = -x², a= -1<0
so the answer is B.kf(x)

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Ad libitum [116K]

The answer would be 6.45

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3 years ago

Alja [10]

Answer:

$1.70

Step-by-step explanation:

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3 years ago

azamat

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3 years ago

iogann1982 [59]

Answer:

Relative minima at $(-\frac{7}{2} , -\frac{49}{4} )$ , and relative maxima DNE.

Step-by-step explanation:

The given function is f(x) = x (x + 7) ...... (1)

We have to calculate the relative maxima and relative minima at point (x, y).

Rearranging the function given above we get.

$y= x^{2} +7x = (x + \frac{7}{2} )^{2} -\frac{49}{4}$

⇒ $y+ \frac{49}{4} = (x + \frac{7}{2} )^{2}$

Now, this is an equation of parabola having vertex at $(-\frac{7}{2} , -\frac{49}{4} )$ and the axis is parallel to positive Y-axis.

Therefore, the function(1) has a relative minima at $(-\frac{7}{2} , -\frac{49}{4} )$ , and the relative maxima DNE. (Answer)

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3 years ago

boyakko [2]

Answer:

6x²

Step-by-step explanation:

3x×2x=6...... then an x²

Therefore answer is 6x²

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2 years ago