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baherus [9]
4 years ago
11

Help with 18 pls?????

Mathematics
1 answer:
zavuch27 [327]4 years ago
5 0
Hello there!

To make x the subject of the formula, we need to start by doing "Cross multiply"

(y)(x) = a

yx = a

Solve for x

Divide both sides by y

yx/y = a/y

x = a/y

Good luck with your studies!

You might be interested in
Write the number that will make the equation true <br> 15-8=__+1
Elis [28]

Answer:

6

Step-by-step explanation:

15-8 =7 as LHS is 7 so RHS must also be 7 so at RHS 6+1 =7

7 0
3 years ago
Two perpendicular lines intersect on the -axis. The equation of one line is y- 4x-6=0. Determine the equation of the other line.
Kay [80]

Answer:

y = -\frac{1}{4}x + 6 or y = -\frac{1}{4}x - 0.375

Step-by-step explanation:

For 2 lines to be perpendicular, their slopes must be <u>negative reciprocals</u>. In order to find the perpendicular of y - 4x - 6 = 0:

SLOPE INTERCEPT FORM: y = 4x + 6

SLOPE OF LINE A: m=4

SLOPE OF LINE B (the one you are looking for): m=-\frac{1}{4}

Since I don't know if you meant that they intercept on the x or y axis I will do both.

<u>y-axis</u>

y-6=-\frac{1}{4}(x-0)

y = -\frac{1}{4}x+6

<u>x-axis</u>

y-0=-\frac{1}{4}(x-1.5)

y=-\frac{1}{4}x-0.375

7 0
3 years ago
Anybody know the answer to this?
fiasKO [112]
It is x=-3 just use Photomath bro
4 0
3 years ago
What is the property of 56+x=x+56?
dem82 [27]
The cumcutative property of addition
5 0
4 years ago
Help based offf order of operations please help
JulijaS [17]

Answer:

The answer for :

h. \:  \:   \: \frac{5}{6}

i. \:  \:  \:  \frac{35}{32}

k. \:  \:  \:  \frac{-29}{20}

l. \:  \:  \:  \frac{13}{15}

Step-by-step explanation:

Question h:

\frac{2}{3}  + ( \frac{1}{3}  \times  \frac{1}{2} )

=  \frac{2}{3}  +  \frac{1}{6}

=  \frac{2 \times 2}{3 \times 2}  +  \frac{1}{6}

=  \frac{4}{6}  +  \frac{1}{6}

=  \frac{5}{6}

Question i:

\frac{7}{8}  +  \frac{1}{4}  \times ( \frac{3}{2}  -  \frac{5}{8} )

=  \frac{7}{8}  +  \frac{1}{4}  \times ( \frac{3 \times 4}{2 \times 4}  -  \frac{5}{8} )

= \frac{7}{8}  +  \frac{1}{4}  \times ( \frac{12}{8}  -  \frac{5}{8} )

=  \frac{7}{8}  +  (\frac{1}{4}  \times  \frac{7}{8} )

=  \frac{7}{8}  +  \frac{7}{32}

=  \frac{7  \times 4}{8 \times 4}  +  \frac{7}{32}

=  \frac{28}{32}  +  \frac{7}{32}

=  \frac{35}{32}

Question k:

\frac{3}{4}  - ( \frac{12}{7}  \div  \frac{12}{21} ) +  \frac{4}{5}

=  \frac{3}{4}  - ( \frac{12}{7}  \times  \frac{21}{12} ) +  \frac{4}{5}

=  \frac{3}{4}  -  \frac{3}{1}  +  \frac{4}{5}

= \frac{3 \times 5}{4 \times 5}  -  \frac{3 \times 20}{1 \times 20} +  \frac{4 \times 4}{5 \times 4}

=  \frac{15}{20}   -   \frac{60}{20} +  \frac{16}{20}

=  -  \frac{29}{20}

Question l:

\frac{5}{2}  \times ( \frac{2}{3}  -  \frac{1}{5} ) - ( \frac{2}{5}  \div  \frac{4}{3} )

=  \frac{5}{2}  \times ( \frac{2 \times 5}{3 \times 5}  -  \frac{1 \times 3}{5 \times 3} ) - ( \frac{2}{5}  \times  \frac{3}{4} )

=  \frac{5}{2}  \times ( \frac{10}{15}  -  \frac{3}{15} ) -  \frac{3}{10}

=  (\frac{5}{2} \times   \frac{7}{15}) -  \frac{3}{10}

=  \frac{7}{6}  -  \frac{3}{10}

=  \frac{7 \times 5}{6 \times 5}  -  \frac{3 \times 3}{10 \times 3}

=  \frac{35}{30}  -  \frac{9}{30}

=  \frac{26}{30}

=  \frac{13}{15}

8 0
3 years ago
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