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4 years ago

11

Help with 18 pls?????

1 answer:

zavuch27 [327]4 years ago

5 0

Hello there!

To make x the subject of the formula, we need to start by doing "Cross multiply"

(y)(x) = a

yx = a

Solve for x

Divide both sides by y

yx/y = a/y

x = a/y

Good luck with your studies!

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Write the number that will make the equation true <br> 15-8=__+1

Elis [28]

Answer:

6

Step-by-step explanation:

15-8 =7 as LHS is 7 so RHS must also be 7 so at RHS 6+1 =7

7 0

3 years ago

Two perpendicular lines intersect on the -axis. The equation of one line is y- 4x-6=0. Determine the equation of the other line.

Kay [80]

Answer:

y = $-\frac{1}{4}$ x + 6 or y = $-\frac{1}{4}$ x - 0.375

Step-by-step explanation:

For 2 lines to be perpendicular, their slopes must be <u>negative reciprocals</u>. In order to find the perpendicular of y - 4x - 6 = 0:

SLOPE INTERCEPT FORM: y = 4x + 6

SLOPE OF LINE A: m=4

SLOPE OF LINE B (the one you are looking for): m= $-\frac{1}{4}$

Since I don't know if you meant that they intercept on the x or y axis I will do both.

<u>y-axis</u>

y-6= $-\frac{1}{4}$ (x-0)

y = $-\frac{1}{4}$ x+6

<u>x-axis</u>

y-0= $-\frac{1}{4}$ (x-1.5)

y= $-\frac{1}{4}$ x-0.375

7 0

3 years ago

Anybody know the answer to this?

fiasKO [112]

It is x=-3 just use Photomath bro

4 0

3 years ago

What is the property of 56+x=x+56?

dem82 [27]

The cumcutative property of addition

5 0

4 years ago

Help based offf order of operations please help

JulijaS [17]

Answer:

The answer for :

$h. \: \: \: \frac{5}{6}$

$i. \: \: \: \frac{35}{32}$

$k. \: \: \: \frac{-29}{20}$

$l. \: \: \: \frac{13}{15}$

Step-by-step explanation:

Question h:

$\frac{2}{3} + ( \frac{1}{3} \times \frac{1}{2} )$

$= \frac{2}{3} + \frac{1}{6}$

$= \frac{2 \times 2}{3 \times 2} + \frac{1}{6}$

$= \frac{4}{6} + \frac{1}{6}$

$= \frac{5}{6}$

Question i:

$\frac{7}{8} + \frac{1}{4} \times ( \frac{3}{2} - \frac{5}{8} )$

$= \frac{7}{8} + \frac{1}{4} \times ( \frac{3 \times 4}{2 \times 4} - \frac{5}{8} )$

$= \frac{7}{8} + \frac{1}{4} \times ( \frac{12}{8} - \frac{5}{8} )$

$= \frac{7}{8} + (\frac{1}{4} \times \frac{7}{8} )$

$= \frac{7}{8} + \frac{7}{32}$

$= \frac{7 \times 4}{8 \times 4} + \frac{7}{32}$

$= \frac{28}{32} + \frac{7}{32}$

$= \frac{35}{32}$

Question k:

$\frac{3}{4} - ( \frac{12}{7} \div \frac{12}{21} ) + \frac{4}{5}$

$= \frac{3}{4} - ( \frac{12}{7} \times \frac{21}{12} ) + \frac{4}{5}$

$= \frac{3}{4} - \frac{3}{1} + \frac{4}{5}$

$= \frac{3 \times 5}{4 \times 5} - \frac{3 \times 20}{1 \times 20} + \frac{4 \times 4}{5 \times 4}$

$= \frac{15}{20} - \frac{60}{20} + \frac{16}{20}$

$= - \frac{29}{20}$

Question l:

$\frac{5}{2} \times ( \frac{2}{3} - \frac{1}{5} ) - ( \frac{2}{5} \div \frac{4}{3} )$

$= \frac{5}{2} \times ( \frac{2 \times 5}{3 \times 5} - \frac{1 \times 3}{5 \times 3} ) - ( \frac{2}{5} \times \frac{3}{4} )$

$= \frac{5}{2} \times ( \frac{10}{15} - \frac{3}{15} ) - \frac{3}{10}$

$= (\frac{5}{2} \times \frac{7}{15}) - \frac{3}{10}$

$= \frac{7}{6} - \frac{3}{10}$

$= \frac{7 \times 5}{6 \times 5} - \frac{3 \times 3}{10 \times 3}$

$= \frac{35}{30} - \frac{9}{30}$

$= \frac{26}{30}$

$= \frac{13}{15}$

8 0

3 years ago