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3 years ago

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One root of the quadratic equation x^2 − 2x + m = 0 is 9. If the other root is n, what is n−m?

1 answer:

mote1985 [20]3 years ago

4 0

$9^2-2*9+m=0\\
\\
81-18+m=0\\
\\
m=-63$

$x^{2} -2x-63=0\\
\\
\Delta=(-2)^2-4.1.(-63)=4+252=256\\
\\
x=\frac{2 \pm 16}{2}\\
\\
x_1=\frac{18}{2}=9\\
\\
n=x_2=\frac{-14}{2}=-7\\
\\
n-n=-7-(-63)=-7+63=56$

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Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

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The smallest possible area (A) = $\frac{1}{16} (\frac{240}{\pi+4})^2+(\frac{60\pi}{\pi+y})^2(\frac{1}{4\pi})$

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