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2 years ago

15

Whats the value of number 3 in 6,035

1 answer:

Sergio039 [100]2 years ago

6 0

<span>When writing a number, the values that given to the numbers are as follows, starting from the right: ones, tens, hundreds, thousands, ten thousands, etc. The three is located on the second position from the right, meaning it is in the tens place. The significance of this is that it has 3 tens, which means its value is 30.I hope that my answer is helpful! Let me know if you need something more :)</span>

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Allison earns a $40,000 base salary plus a commission equal to 15% of your total sales if you are in $70,000 last year what was

Anettt [7]

15/100*70000=$10500
$40000+$10500= $50,000

5 0

3 years ago

Multiply.<br> (3x + 1)(2x – 1)<br><br> Answer plz

DENIUS [597]

Answer:

$= 3x + 1 + 2x - 1 \\ = 3x + 2x + 1 - 1 \\ = 5x + 0 \\ = 5x$

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3 years ago

Read 2 more answers

It costs $3 to bowl a game and $2 for shoe rental.

gulaghasi [49]

Expression: 3g+2
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3 0

3 years ago

2/3x=20 help mee if you dont mind

Ksenya-84 [330]

The answer I got was 30

7 0

3 years ago

Can I get some help, it is due in 15 minutes and I need help. Thanks, any help appreciated

koban [17]

Well, I'm way past the 15 min mark, but here's how to do the question.

With this, you will need to use the distance formula, $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ , on XY, YZ, and ZX.

XY: $\sqrt{(3-1)^2+(1-6)^2}$

Firstly, solve inside the parentheses: $\sqrt{(2)^2+(-5)^2}$

Next, solve the exponents: $\sqrt{4+25}$

Next, solve the addition, and XY's distance will be √29

(The process is the same with the other 2 sides, so I'll go through them real quickly)

YZ:

$\sqrt{(6-3)^2+(3-1)^2}\\ \sqrt{(3)^2+(2)^2}\\ \sqrt{9+4}\\ \sqrt{13}$

ZX:

$\sqrt{(1-6)^2+(6-3)^2}\\ \sqrt{(-5)^2+(3)^2}\\ \sqrt{25+9}\\ \sqrt{34}$

Now that we got the 3 sides, we can add them up: $\sqrt{29}+\sqrt{13} +\sqrt{34} =14.8$

In short, your answer is 14.8, or the second option.

8 0

3 years ago