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lozanna [386]
4 years ago
6

Jay Feltcher deposited $3,400 into a retirement account. Find the rate if he has $3,494.50 in the account 9 months later.

Mathematics
2 answers:
Tom [10]4 years ago
8 0
7.4 is the correct answer
wlad13 [49]4 years ago
6 0

Answer:

3.7%

Step-by-step explanation:

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Can somebody help me????
ddd [48]
f(x)=5x^2-3\\\\\\
f(x+a)=5(x+a)^2-3=5(x^2+2ax+a^2)-3=\\\\=\boxed{5x^2+10ax+5a^2-3}

On the other hand:

f(x+a)=5x^2+30x+42

so:

10ax=30x\\\\10a=30\qquad|:10\\\\\boxed{a=3}

Answer C.
8 0
4 years ago
When added, what is the simplified form of (7 + 2i) + (3 + 6i)? Write the answer in standard form, a + bi, where a and b are rea
Liula [17]

9514 1404 393

Answer:

  10 +8i

Step-by-step explanation:

You add these the same way you would if they were considered to be polynomials.

  (7 +2i) +(3 +6i) = (7 +3) +(2 +6)i = 10 +8i

5 0
3 years ago
A man buys lemons at 3 for Rs. 5 and an equal number at 2 for Rs. 4. He mixes them and sells at 5 for Rs. 9. Find his gain or lo
melamori03 [73]

3 lemons cost = Rs. 5

Each lemon cost = Rs. 5/3

2 lemons Cost = Rs. 4

Each lemon cost =

= \frac{4}{2}  =  \frac{2}{1}  = 2

Total Cost price of Each lemon =

\frac{5}{3}  +   \frac{2}{1}

LCM = 3

\frac{5}{3}  +  \frac{2 \times 3}{1 \times 3}  =  \frac{6}{3}  =  \frac{5 + 6}{3}  =  \frac{11}{3}

Each lemon Cost =

=  \frac{11}{3}  \div  \frac{2}{1}

=  \frac{11}{3}  \times  \frac{1}{2}

=  \frac{11}{6}

Selling price of 5 lemons = 9

Selling price of 1 lemon = 9/5

loss\% =  \frac{loss \times 100}{CP}

=  \frac{ \frac{4}{6} -  \frac{9}{5}  \times 100 }{ \frac{11}{6} }

=    \frac{\frac{55 - 54}{30} \times 100}{ \frac{11}{6} }

=   \frac{\frac{1}{30}  \times 100}{ \frac{11}{6} }

=  \frac{100}{30}  \times  \frac{6}{11}

=  \frac{20}{1}  = 1 \frac{9}{11} \% \: loss

5 0
3 years ago
Read 2 more answers
Can anyone help me with this ?
STALIN [3.7K]

To solve this problem use the formula below. All you have to do is insert the respective points into the formula and it gives you the radical form.

6 0
3 years ago
Please help me with this please!!
Eva8 [605]

9514 1404 393

Answer:

  135°

Step-by-step explanation:

In order to answer the question, we must assume that the black lines are parallel to each other.

The given angles (2, 8) are "same-side (consecutive) exterior" angles, so are supplementary.

  ∠2 +∠8 = 180°

  15x +5x = 180°

  x = 180°/20 = 9°

  ∠2 = 15x = 15(9°) = 135°

Angles 2 and 3 are vertical angles, so angle 3 has the same measure as angle 2.

  ∠3 = 135°

6 0
3 years ago
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