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tresset_1 [31]
4 years ago
8

Can somebody help me????

Mathematics
1 answer:
ddd [48]4 years ago
8 0
f(x)=5x^2-3\\\\\\
f(x+a)=5(x+a)^2-3=5(x^2+2ax+a^2)-3=\\\\=\boxed{5x^2+10ax+5a^2-3}

On the other hand:

f(x+a)=5x^2+30x+42

so:

10ax=30x\\\\10a=30\qquad|:10\\\\\boxed{a=3}

Answer C.
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