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belka [17]
3 years ago
10

Marcellus sent four faxes to Gem. The first fax took 14 seconds to send, the second fax 19 seconds, the third 16 seconds, and th

e fourth 11 seconds. Use mental math to find out how many seconds it took to fax all four documents to Gem. Explain your reasoning
Mathematics
2 answers:
Scrat [10]3 years ago
8 0

It took 60 seconds to fax all documents to Gem

Step-by-step explanation:

The simple addition has to be done to solve the given problem

Given

total faxes = 4

Time for fax 1: t_1 = 14\ sec

Time for fax 2: t_2 = 19\ sec

Time for fax 3: t_3 = 16\ sec

Time for fax 4: t_4 = 11\ sec

The total time t will be:

t = t_1+t_2+t_3+t_4\\= 14+19+16+11\\= 60\ sec

Hence,

It took 60 seconds to fax all documents to Gem

Keywords: Time, addition

Learn more about addition at:

  • brainly.com/question/9231234
  • brainly.com/question/9214411

#LearnwithBrainly

sweet [91]3 years ago
6 0

Answer: 60 seconds

Step-by-step explanation:

14 +19 +16 +11

= 60 seconds to fax all the document to gem

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8 0
3 years ago
Read 2 more answers
Consider the fibonacci sequence below, which is the first term in the sequence to exceed 120?
gizmo_the_mogwai [7]

Answer:

144

Step-by-step explanation:

The sequence is:

0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610, 987, 1597, 2584, 4181, 6765, 10946

so you can see the first term larger than 120 is the 144.

3 0
3 years ago
1+4=5, 2+5=12, 3+6=21 , 8+11=? WHAT THE CORRECT ANSWER?/
Lorico [155]
The answer is 40, take 21 from the last equation solved and add 8 to it then add 11
6 0
3 years ago
Andrew owns 3 fewer DVDs than Paul. Let K represent number of Paul's DVDs. Write the expression that can be used to find the num
Julli [10]
K-3 should be the answer because andrew has 3 less than Paul.

5 0
3 years ago
The line 3x-8y=k cuts the x-axis and y- axis at the point A and B respectively. If the area of ∆AOB =12sq.units, find the value
Sladkaya [172]

Given:

The equation is:

3x-8y=k

It cuts the x-axis and y- axis at the point A and B respectively.

The area of ∆AOB =12 sq.units.

To find:

The value of <em>k</em>.

Solution:

We have,

3x-8y=k

Substituting x=0 to find the y-intercept.

3(0)-8y=k

0-8y=k

y=\dfrac{k}{-8}

y=-\dfrac{k}{8}

Substituting y=0 to find the x-intercept.

3x-8(0)=k

3x-0=k

x=\dfrac{k}{3}

Area of a triangle is:

A=\dfrac{1}{2}\times base\times height

The height of the ∆AOB is OB=\dfrac{k}{8} because distance cannot be negative and the base of the ∆AOB is OA=\dfrac{k}{3}. So, the area of the ∆AOB is:

A=\dfrac{1}{2}\times \dfrac{k}{8}\times \dfrac{k}{3}

A=\dfrac{k^2}{48}

It is given that, the area of ∆AOB = 12 sq.units.

\dfrac{k^2}{48}=12

k^2=576

k=\pm \sqrt{576}

k=\pm 24

Therefore, the value of k is either 24 or -24.

4 0
3 years ago
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