Answer:
Ix = Iy =
Radius of gyration x = y = 
Step-by-step explanation:
Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.
Mass of disk = ρπR2
Moment of inertia about its perpendicular axis is
. Moment of inertia of quarter disk about its perpendicular is
.
Now using perpendicular axis theorem, Ix = Iy =
=
.
For Radius of gyration K, equate MK2 = MR2/16, K= R/4.
Answer:
the answer might be either one of the four
Answer:
<h2>

</h2>
Step-by-step explanation:
f(x) = 2x + 4
g(x) = 4x² + 1
In order to find (g ∘ f)(0) we must first find
(g ° f )(x)
To find (g ° f )(x) substitute f(x) into g(x) that's for every x in g(x) replace it with f(x)
That's
<h3>

</h3>
We have
<h3>

</h3>
Now to find (g ∘ f)(0) substitute the value of x that's 0 into (g ∘ f)(0)
We have
<h3>

</h3>
We have the final answer as
<h3>

</h3>
Hope this helps you
Did you mean this? <span>3^2x+1=3^x+5 => 3^(2x+1) = 3^(x+5)? If so, then 2x+1 is necessarily equal to x+5, so that 2x+1=x+5. Thus, x = 4 (answer).
Those parentheses are not optional; they must be part of your problem statement and solution.</span>