Option C:
x = 6 units
Solution:
QR = 7 units, RS = 5 units, UT = 4 units and ST = x
<em>If two secants intersect outside a circle, the product of the secant segment and its external segment s equal to the product of the other secant segment and its external segment.</em>
⇒ SR × SQ = ST × SU
⇒ 5 × (5 + 7) = x × (x + 4)
⇒ 5 × 12 = x² + 4x
⇒ 60 = x² + 4x
Subtract 60 from both sides.
⇒ 0 = x² + 4x - 60
Switch the sides.
⇒ x² + 4x - 60 = 0
Factor this expression, we get
(x - 6)(x + 10) = 0
x - 6 = 0, x + 10 = 0
x = 6, x = -10
Length cannot be in negative measures.
x = 6 units
Option C is the correct answer.
The answer should be
c) (-2,5)
It is the only point that falls on the line and when you count the units from (-7,2) to (-2,5) it is 5 units and when you count the distance from (3,8) to (-2,5) you also get 5 units, proving that (-2,5) is in the middle of the line.
There are 2 significant figures in 85 000
Answer/Step-by-step explanation:
a. m<h = x°
Two angles to use in finding x are <h and 55°
Angle pair formed: linear pair angles
b. x° + 55° = 180° (linear pair)
Subtract 55° from each side
x + 55 - 55 = 180 - 55
x = 125°
c. Given: m<n = y°
Two angles to use in solving for y are: <h and <n
Angle pair formed: alternate exterior angles
d. m<n = y° (given)
m<n = x° = 125° (as solved in 2b)
Therefore:
y = x (alternate exterior angles are congruent)
thus:
y = 125° (substitution)
Answer:
y=5/2x+6
Step-by-step explanation:
