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Furkat [3]
3 years ago
6

How many significant digits are in this number 85 000?

Mathematics
2 answers:
Artyom0805 [142]3 years ago
6 0
A significant digit is a number that is used to express the required degree of accuracy, starting from the first non zero number. Therefore the number of significant digits in the number 85,000 is two: 8 & 5.
Tpy6a [65]3 years ago
5 0
There are 2 significant figures in 85 000
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I'm stuck on this question can anyone help??
Aleksandr-060686 [28]
The answer to this is letter C: <em>This equation is an example of converting by using proportion.</em> The proportion used here is the measurement of something in inches to the measurement of something in ft. The ratio would always be constant, hence, the equality sign. 
6 0
3 years ago
Hiya! Here's my question:
Step2247 [10]

wait i got it!

Since 18 kilograms are 18000 grams, you have

18000/30=600

and

800/30=26.6

So, with 18 kilograms of salt the baker can make exactly 600 batches with no leftovers, while with 800 grams of salt the baker can make 26 batches, with some leftovers.

In fact, 26 batches require

26 x 30 =780

grams of salt, and the remaining

800-780=20

grams of salt are not enought to prepare the next batch

Step-by-step explanation:

5 0
3 years ago
Select all the numbers that show 4% as an equivalent fraction, decimal, or percent.
drek231 [11]
0.04 is the only right one
4 0
3 years ago
Read 2 more answers
Find a fraction between 3/4 and 4/5
-Dominant- [34]
First, find a common denominator: 40 then, convert the fractions: 30/40 and 32/40 between those two, it would be 31/40 answer: 31/40
7 0
4 years ago
How many five-digit numbers are there that contain the digit 1 (at least) three times in a row?
My name is Ann [436]

Answer:

So you say you want some 5 digit numbers eh? Let’s consider some boundaries. 5 digit numbers range from 10,000 - 99,999. So our number is guaranteed to be between 0 and 90000.

Sometimes it’s much easier to work with concrete things. Such as the number of numbers that don’t contain any 3s. It’s really more difficult to put our finger on “at least 1” anything so we try to steer clear of it.

Anyways we’ve got 90000 numbers that have at least 1 or 0 3’s. Find one and we know the other.

So no 3’s at all right? Well you have 8 choices for the first digit (can’t choose 0 and you can’t choose 3). And then for the remaining 4 digits you have 9 choices. So that’s

8∗94=52488  

Back to our initial equation, we have

90000−8∗94=37512  5 digits numbers without any 3s.

A quick (or maybe not so quick) matlab script confirms such calculations.

credits to : Trevor Squires

7 0
3 years ago
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