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3 years ago

lie is solving the quadratic equation by completing the square. 3x2 + 18x – 8 = 0 3x2 + 18x = 8 What should Lie do next?

Mathematics

2 answers:

ra1l [238]3 years ago

8 0

Answer: In the next step, he takes the factor 3 out of the variable terms and divide it to the other side.

Step-by-step explanation:

ruslelena [56]3 years ago

3 0

Divide 18 by 2(9) then square that (81). add 81 to both sides

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Give a example of term in math

Viefleur [7K]

7x or just x

Both of them are terms when they have a variable next to it

5 0

3 years ago

At a pet store, one fifth of the animals are cats and three-fourth are fish. There are 40 animals at the pet store. How many are

dybincka [34]

Answer:

2 animals

Step-by-step explanation:

Number of animals=40

Fraction of fish=3/4

=>number of fish=3/4*40=30

Fraction of cats=1/5

=>number of cats=1/5*40=8

Animals which are not cats or fish are=total number of animals-(number of cats + number of fish)

Animals which are not cats or fish=40-(8+30)

40-38

2 animals

7 0

3 years ago

In the arithmetic sequence, -12, -17, -22, -27... which term has a value of -68?

RSB [31]

Answer:

-68 is not a term in the given sequence

Step-by-step explanation:

The given sequence is -12, -17, -22, -27...

There is a common difference of d=-17--12=-5

The explicit rule for this sequence is $f(n)=-12-5(n-1)$

Or $f(n)=-5n-7$

To find the term that has a value of -68 we equate the explicit formula and solve for n.

$-68=-5n-7$

$\implies -68+7=-5n$

$\implies -61=-5n$

$n=\frac{61}{5} =12.2$

The position should be a natural number.

Since n is a decimal, it tells us that -68 is not a term in the given sequence

7 0

3 years ago

What is the 7th term of the geometric sequence 4, -20, 100

Sloan [31]

1st let's calculate r the common ratio:
r = (-20)/4 = (100/-20) = -5

Value of nth term = a₁.rⁿ⁻¹, where a₁= 1st term and n, the rank

Value of nth term = 4r⁽⁷⁻¹⁾ = 4.(-5)⁶

Value of nth term = 62,500

4 0

3 years ago

How do extraneous solutions arise from radical equations?

AnnyKZ [126]

You get extraneous solutions anytime the radical becomes undefined under the set of real numbers. for example $\sqrt{-1}$ does not exsist since the radical cannot be used on a negative number

5 0

3 years ago