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yan [13]
3 years ago
13

If a man earns $420 interest in one year at 7%, what was the amount of money invested?

Mathematics
1 answer:
nordsb [41]3 years ago
3 0
I(interest)=P(princple)R(rate)T(time)
I=420*.07*1=$29.4
A is correct.
Peace.
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Work out the unknown angles. Give reasons for each answer.
zalisa [80]
A)

Because the sum of angles in a triangle must equal 180° we can say:

62+α+90=180

α+152=180

α=28°

b)

Since all sides have equal length, all angles must have equal measure.  (This is an equilateral triangle).  And again, because the sum of the angle must be 180° we can say:

b+b+b=180

3b=180

b=60°
8 0
3 years ago
If (5x-3y)²=0, then x/y=?​
alexandr1967 [171]

Answer:

\frac{3}{5}

Step-by-step explanation:

Given

(5x - 3y)² = 0, then

5x - 3y = 0 ( add 3y to both sides )

5x = 3y (divide both sides by 5 )

x = \frac{3}{5} y ( divide both sides by y )

\frac{x}{y} = \frac{3}{5}

5 0
3 years ago
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Determine the equations of the vertical and horizontal asymptotes, if any, for y=x^3/(x-2)^4
djverab [1.8K]

Answer:

Option a)

Step-by-step explanation:

To get the vertical asymptotes of the function f(x) you must find the limit when x tends k of f(x). If this limit tends to infinity then x = k is a vertical asymptote of the function.

\lim_{x\to\\2}\frac{x^3}{(x-2)^4} \\\\\\lim_{x\to\\2}\frac{2^3}{(2-2)^4}\\\\\lim_{x\to\\2}\frac{2^3}{(0)^4} = \infty

Then. x = 2 it's a vertical asintota.

To obtain the horizontal asymptote of the function take the following limit:

\lim_{x \to \infty}\frac{x^3}{(x-2)^4}

if \lim_{x \to \infty}\frac{x^3}{(x-2)^4} = b then y = b is horizontal asymptote

Then:

\lim_{x \to \infty}\frac{x^3}{(x-2)^4} \\\\\\lim_{x \to \infty}\frac{1}{(\infty)} = 0

Therefore y = 0 is a horizontal asymptote of f(x).

Then the correct answer is the option a) x = 2, y = 0

3 0
3 years ago
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Arrange the following numbers in order from greatest to least: 7,361;7614
stepladder [879]
7,614 ,7,361,
Hope this helped.
6 0
3 years ago
8.) 2x<12 pls help me
Roman55 [17]

Answer:

x < 6

Step-by-step explanation:

2x < 12

Divide both sides by 2;

x < 6

x is less than 6

3 0
2 years ago
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