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3 years ago

If a man earns $420 interest in one year at 7%, what was the amount of money invested?

Mathematics

1 answer:

nordsb [41]3 years ago

3 0

I(interest)=P(princple)R(rate)T(time)
I=420*.07*1=$29.4
A is correct.
Peace.

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The base of the pyramid is a regular hexagon. Find the volume of the pyramid. Round your answer to the nearest tenth.

alexandr402 [8]

Answer:

216.5

Step-by-step explanation:

Pyramid volume=(area of the base)*(height)/3

Pyramid volume=(area of hexagon with side 5)*(height)/3

Area of hexagon is 3*sqrt(3)*(side)^2/2=75*sqrt(3)/2

Pyramid volume=10*(75*sqrt(3))/(2*3)=216.5

7 0

3 years ago

I require assistance with this problem.<br> Solve for X:<br> 5/10 + 1/x = 5/6

BabaBlast [244]

Answer:

x = 3

Step-by-step explanation:

Solve for x:

1/2 + 1/x = 5/6

Bring 1/2 + 1/x together using the common denominator 2 x:

(x + 2)/(2 x) = 5/6

Cross multiply:

6 (x + 2) = 10 x

Expand out terms of the left hand side:

6 x + 12 = 10 x

Subtract 10 x + 12 from both sides:

-4 x = -12

Divide both sides by -4:

Answer: x = 3

4 0

3 years ago

Read 2 more answers

How many solutions does the equation 6a - 3a - 6 = 2 + 3 have?

Softa [21]

Answer:

One, a=11/3.

Step-by-step explanation:

6a-3a-6=2+3

3a-6=5

3a=5+6

3a=11

a=11/3

5 0

3 years ago

Slope of (-4, -3) and (14, 0)

rewona [7]

Answer:

slope of (-4,-3)- 0

slope of (14,0)- 2

Step-by-step explanation:

3 0

3 years ago

A random sample of 10 shipments of stick-on labels showed the following order sizes.10,520 56,910 52,454 17,902 25,914 56,607 21

sammy [17]

Answer:

Confidence Interval: (21596,46428)

Step-by-step explanation:

We are given the following data set:

10520, 56910, 52454, 17902, 25914, 56607, 21861, 25039, 25983, 46929

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{340119}{10} = 34011.9$

Sum of squares of differences = 551869365.6 + 524322983.6 + 340111052.4 + 259528878 + 65575984.41 + 510538544 + 147644370.8 + 80512934.41 + 64463235.21 + 166851472.4 = 2711418821

$S.D = \sqrt{\frac{2711418821}{9}} = 17357.09$

Confidence interval:

$\mu \pm t_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 9 and}~\alpha_{0.05} = \pm 2.2621$

$34011.9 \pm 2.2621(\frac{17357.09}{\sqrt{10}} ) = 34011.9 \pm 12416.20 = (21595.7,46428.1) \approx (21596,46428)$

7 0

3 years ago