All categories

3 years ago

What is 14abc+3a-5b+6c

2 answers:

7 0

Given 3A = 4B
MEANS 3/4 = B/A or 3:4 = B :A ------------------1 
NOW 4B = 6C 
means 4/6 = C/B OR 4 : 6 = C : B - OR 2 : 3 is C : B-------------------------- ----2 
AND 3A = 6C 
MEANS 3/6 = C/A or 3:6 = C : A 
hence A ;B : C = 4 : 3 : 2 <---- is the answer!

Vlad1618 [11]3 years ago

5 0

-1

1*-1=-1
that's your answer
have a good day

You might be interested in

Show that x2 +x-3=0 has a solution between 1 and 2

Natali5045456 [20]

Answer:

here is the answer

Step-by-step explanation:

hope it is helpful

7 0

3 years ago

Nearest ten thousand 384400

olga_2 [115]

Answer:

The nearest ten thousand is 80,000.

8 0

3 years ago

Plz help

astraxan [27]

Cost of dried fruit per pound=2.5 $/pound
cost of nuts per pound =2 $/pound
total cost=225$ =cost of dried fruit +total cost of nuts
To find the cost of dried fruit we need to multiply cost of dried fruit per pound and the number of bounds hence 2.5 x where x is the number of bounds
which is the total cost of dried fruit and consequently 2y is total cost of nuts where y is the weight of nuts in pound

6 0

3 years ago

Convert 100 km/h to m/s.

solniwko [45]

100 * 1000 : 60 : 60 = 27.77 m/s

5 0

4 years ago

A health statistics agency in a certain country tracks the number of adults who have health insurance. Suppose according to the

Nana76 [90]

Answer:

a) There is a 15.3% probability that a randomly selected person in this country is 65 or older.

b) Given that a person in this country is uninsured, there is a 2.2% probability that the person is 65 or older.

Step-by-step explanation:

We have these following percentages:

5.3% of those under the age of 18, 12.6% of those ages 18–64, and 1.3% of those 65 and older do not have health insurance.

22.6% of people in the county are under age 18, and 62.1% are ages 18–64.

(a) What is the probability that a randomly selected person in this country is 65 or older?

22.6% are under 18

62.10% are 18-64

The rest are above 65

100% - (22.6% + 62.10%) = 15.3%

There is a 15.3% probability that a randomly selected person in this country is 65 or older.

b) Given that a person in this country is uninsured, what is the probability that the person is 65 or older?

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

So, what is the probability that a person is 65 and older, given that the person is uninsured.

P(B) is the probability that a person is 65 and older. From a), we have that $P(B) = 0.153$

P(A/B) is the probability is uninsured, given that that person is 65 and older. So $P(A/B) = 0.013$

P(A) is the probability that a person is uninsured. That is the sum of 5.3% of 22.6%, 12.6% of 62.1% and 1.3% of 15.3%. So:

$P(A) = 0.053*(0.226) + 0.126*(0.621) + 0.013*(0.153) = 0.0922$

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.153*0.013}{0.0922} = 0.022$

Given that a person in this country is uninsured, there is a 2.2% probability that the person is 65 or older.

6 0

3 years ago