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kow [346]
4 years ago
15

Emma is training for a 10-kilometer race. She wants to beat her last 10-kilometer time, which was 1 hour 10 minutes. Emma has al

ready run for 55 minutes. Which inequality can be used to find how much longer she can run and still beat her previous time? (1 hr = 60 min)

Mathematics
2 answers:
Sauron [17]4 years ago
4 0

Answer:

70 > I+55

Step-by-step explanation:

The last inequality expresses better this situations.

Emma wants to beat her last record, which was 70 minutes. So, she needs to run in less than 70 minutes.

However, she already ran 55 minutes, the remaining time would be the variable I, so, the sum of them must be less than 70 minutes. So, there are two options to represent this:

I + 55 < 70 or 70 > I + 55.

And if this helped you, feel free to make this the brainliest answer!

yanalaym [24]4 years ago
4 0

Answer:

(D) 70 greater-than t + 55   =  70>t+55

Step-by-step explanation:

70 greater-than 7 minus 55

70 less-than t minus 55

70 less-than-or-equal-to t + 55

70 greater-than t + 55

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I need help please :(
zloy xaker [14]

Answer:

-(1/3 · 1/3 · 1/3 · 1/3 )

Step-by-step explanation:

-(3)^-4= -1/3 ^4 = -1/81

-(1/3 · 1/3 · 1/3 · 1/3 )= -1/81

7 0
3 years ago
Read 2 more answers
Is 1third =to 1sixth
NNADVOKAT [17]

Answer: No, 1/3 is equal to 2/6

Step-by-step explanation: If you multiply the bottom number, the denominator, and the top number, the numerator, by 2, you will get 2/6 which is equal to 1/3.

3 0
4 years ago
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PLEASE HELP WITH MY MATH
poizon [28]

1. 10 ft

2. 15 ft

3. 36 meters

4. 4 ft

Hope this helps!

4 0
4 years ago
Why would I rewrite this
Ratling [72]

You are finding 3 1/6 - 1 5/6.

To solve, you should first change it so that the numerator of the first fraction is greater than the numerator of the second. Note that both have the same denominator (6). Subtract as usual:

3 1/6 = 2 7/6

2 7/6 - 1 5/6 = 1 2/6

1 2/6 is your answer.

~

7 0
4 years ago
Write an equation for the nth term of the geometric sequence 6000,3000,1500,750 <br> PLEASE HELP!!!
Wewaii [24]

Answer: 6000\cdot (1/2)^{n-1}

Each term is half of the previous one, so the common ratio is 1/2. Then to get from the first term to the nth term, you have to take n - 1 steps, multiplying by 1/2 each time and by 6000 to account for the first term.

i hope this helps! :D

8 0
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