Just solve.
Solve and find the integer of 4x^2-19x-5
1 answer:
(x-5)(4x+1)
4x^2 times -5 is -20 the factors of -20 are -1x20, 1x-20... but to make the -19x you would add together the 1 and -20 because 1-20 is -19.
This then splits off to factorise 4x^2-20x, making this side 4x(1x-5) carry the brackets over to make it 1(1x-5) joining the brackets together to make (4x+1)(x-5)
4x^2 times -5 is -20 the factors of -20 are -1x20, 1x-20... but to make the -19x you would add together the 1 and -20 because 1-20 is -19.
This then splits off to factorise 4x^2-20x, making this side 4x(1x-5) carry the brackets over to make it 1(1x-5) joining the brackets together to make (4x+1)(x-5)
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Answer:
Q1. 1050 miles
Q2. 1h 30m
Step-by-step explanation:
Q1. 1h = 300 miles
3h = 3.5 × 300 miles
= 1050 miles
Q2. 68km = 1h
102km = × 1h
= 1.5h
= 1h 30m