Question

HELP!!!

Answer 1

In the right triangle ABC, right angled at A.

AB=6 , BC=12.

We have to find the value of Cot C.

In the right triangle ABC,

By using the Pythagoras theorem, which states

$(BC)^{2}=(AB)^{2}+(AC)^{2}$

$(12)^{2}=(6)^{2}+(AC)^{2}$

$(AC)^{2}=108$

$(AC)=\sqrt{108}$

$AC = 6\sqrt{3}$

Now, we will determine the value of Cot C.

Since, $\cot \Theta =\frac{Base}{Perpendicular}$

$\cot C =\frac{AC}{AB}$

$\cot C =\frac{6\sqrt{3}}{6}$

$\cot C =\sqrt{3}}$

So, the value of Cot C is radical sign 3.

So, Option A is the correct answer.

Answer 2

The answer is A. Radical sign 3.