A. Half of the original number\
Answer:
At most, Liam can only buy lunch for 6 people.
Step-by-step explanation:
It isn't going to be a decimal answer because there can't be half of a person
All you have to do is divide 50 by 8 and round down because you don't want to spend more than 50 dollars.
Writing it mathematically, it would be:
p
6
Answer:
![H_{0}: \mu \leq 600\text{ dollars}\\H_A: \mu > 600\text{ dollars}](https://tex.z-dn.net/?f=H_%7B0%7D%3A%20%5Cmu%20%5Cleq%20600%5Ctext%7B%20dollars%7D%5C%5CH_A%3A%20%5Cmu%20%3E%20600%5Ctext%7B%20dollars%7D)
Step-by-step explanation:
We are given the following in the question:
Manager's claim: The mean guest bill for a weekend is $600 or less.
A member of the hotel’s accounting staff noticed that the total charges for guest bills have been increasing in recent months.
A sample of weekend guest bills were collected to test the manager’s claim.
We design the null and alternate hypothesis in the following manner:
![H_{0}: \mu \leq 600\text{ dollars}\\H_A: \mu > 600\text{ dollars}](https://tex.z-dn.net/?f=H_%7B0%7D%3A%20%5Cmu%20%5Cleq%20600%5Ctext%7B%20dollars%7D%5C%5CH_A%3A%20%5Cmu%20%3E%20600%5Ctext%7B%20dollars%7D)
Conclusion when null hypothesis cannot be rejected:
When we fail to reject the null hypothesis and accept the null hypothesis, thus, we have enough evidence to support the manager's claim that the mean guest bill for a weekend is $600 or less.
Conclusion when null hypothesis can be rejected:
When the null hypothesis is rejected, we accept the alternate hypothesis.
Thus, there are not sufficient evidence to support the manager's claim that the mean guest bill for a weekend is $600 or less.
X => -8 -6 -8 3
y => 33 31 39 33
is not a function because the x value -8 results to two different y-values 33 and 39.
3/5 I think is the answer