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4 years ago

5

What's the distance between the points (–9,2) and (–4,2)?

1 answer:

algol [13]4 years ago

7 0

If you are asking for the slope it is a zero slope because...

2-2 equals 0 and you don't need to solve the bottom because the top is a zero

but a horizontal slope is when the zero is on the bottom.

btw- I guarantee I am right because i am a Indian. My wisdom comes from God. Jesus Christ!!!!:):):)

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Please help! Need em doneee

kogti [31]

Letter C

Use the Distance formula
sq rt [ (x2 - x1)^2 + (y2 - y1)^2 ]

sq rt [ (10-5)^2 + (2 - 4)^2 ]
sq rt [ (5)^2 + (-2)^2 ]
sq rt ( 25 + 4)
Square root of 29

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1 year ago

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PLEASE HELP IM STUCK

Tanzania [10]

Y= -1/2x + 3 i believe is corréate

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2 years ago

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Which of the following options results in a graph that shows exponential growth. F(x) = 0.4(3)^x. F(x) = 3(0.5)^x. F(x) = 0.8(0.

Andre45 [30]

$f(x)=a^x\\\\if\ a \ \textgreater \ 1\ then\ a\ function\ is\ an\ exponential\ growth\ function$

$f(x)=0.4(3)^x\to a=3 > 1\ OK!\\f(x)=3(0.5)^x\to a=0.5 < 1 :(\\f(x)=0.8(0.9)^x\to a=0.9 < 1 :(\\f(x)=0.9(5)^{-x}=0.9\left(\dfrac{1}{5}\right)^x\to a=\dfrac{1}{5} < 1\ :($

Answer: $f(x)=0.4(3)^x$

5 0

3 years ago

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). Complete the st

Zina [86]

Question:

If cos(θ) =-8/17 and sin(θ) is negative, then sin(θ) = ___ and tan(θ) =___.

Answer:

$Sin\theta = \frac{-15}{17}$

$Tan\theta = \frac{15}{8}$

Step-by-step explanation:

Given

cos(θ) =-8/17

Required

sin(θ) = __

tan(θ) =__

The first step is to determine the length of the third side

Given that

$cos(\theta) = \frac{Adj}{Hyp}$

Where Adj and Hyp represent Adjacent and Hypotenuse

$cos(\theta) = \frac{-8}{17}$

By comparison

$Adj = -8\ and\ Hyp = 17$

Using Pythagoras

$Hyp^2 = Adj^2 + Opp^2$

By Substitution

$17^2 = (-8)^2 + Opp^2$

$289 = 64 + Opp^2$

Subtract 64 from both sides

$289 - 64 = 64 - 64 + Opp^2$

$225 = Opp^2$

Take square roots of both sides

$\sqrt{225} = \sqrt{Opp^2}$

$\sqrt{225} = Opp$

$15 = Opp$

$Opp = 15$

The question says that sin(θ) is negative; This implies that θ is in the third quadrant and as such

$Opp = -15$

From trigonometry

$Sin\theta = \frac{Opp}{Hyp}$

$Sin\theta = \frac{-15}{17}$

Also from trigonometry

$Tan\theta = Sin\theta / Cos\theta$

$Tan\theta = \frac{-15}{17} / \frac{-8}{17}$

$Tan\theta = \frac{-15}{17} * \frac{-17}{8}$

$Tan\theta = \frac{-15 * -17}{17 * 8}$

$Tan\theta = \frac{15 * 17}{17 * 8}$

$Tan\theta = \frac{15}{8}$

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3 years ago

Add and simplify 7/8+ 1/6

Svet_ta [14]

Answer:

17/24

Step-by-step explanation:

4 0

3 years ago

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