We need to be able to see the graphs, can you add a picture? If you do have one, than sorry, but it won’t load.
Depending on the size of the track but from what I know, they are normally 400 meters for 1 lap. All you need to do is 5000 divided by 400 which is 12.5 so 5000 meters is 12 and a half laps around the track.
OK so we need to find the function v(t) which will tell us where the particle is at any given time.
We know that the derivative of distance is speed and the derivative of speed is acceleration.
In this case we need to work backwords and find the integrals.
a(t) = 13 sin(t) + 4 cos(t)
s(t)= integral of above = 13(-cos(t)) + 4(sin(t)) + C
v(t)= integral of above = -13sin(t) -4cos(t) +Ct + D
Now I believe you have incorrect initial conditions
s(0) = 0, s(2π) = 10
As cos and sin functions have the same value at 0 and 2Pi the above cannot be true.
My guess is that one is s(0) and the other is v(2Pi) or the other way round.
These initial conditions will determine the value of the two constants: C and D.
Hope this helps.
Answer:
EF=3.6
Step-by-step explanation:
I'm going to use Pythagorean Theorem for side EF.
4.8^2+EF^2=6^2
23.04+EF^2=36
-23.04 -23.04
EF^2=12.96
sqrt sqrt
EF=3.6
Answer:
what's the question here if ur asking how long It'll take it's 45
