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-Dominant- [34]
3 years ago
11

A poll showed that of the 108 people at the park, 19 of them had at least one pet. How many of the people at the park had at lea

st one pet?
Mathematics
2 answers:
Semenov [28]3 years ago
3 0
19 unless 19 is a percent then its gonna be 76 people

Lilit [14]3 years ago
3 0

Answer:

19 i got it right

Step-by-step explanation:

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Will give brainliest to whoever replies with the correct answer. (Question is in the image)
EastWind [94]

Answer:x = 7

Step-by-step explanation:

Similar figures have sides that are proportional.  Setting up a proportion for the sides of the figures will help solve for 'x':

Cross-multiply:  3(x + 1) = 6(x - 3)

Distribute:  3x + 3 = 6x - 18

Combine like terms:  21 = 3x

Solve for 'x':  x = 7

5 0
3 years ago
6. A number j increased by 8 *
e-lub [12.9K]

Answer:

6. b. j+ 8

7. b. n - 2

8. a. Addition

9. d. y ÷ -5

10. c. 18 - 19

11. a. 10 + 6

12. b. Divided by

13. a. three added to 5

14. b. 9

15. b. 75

8 0
3 years ago
WILL MARK BRAINLIEST !!!
Finger [1]

Answer:

2:5

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The indicated function y1(x) is a solution of the associated homogeneous equation. Use the method of reduction of order to find
Serga [27]

Answer:

Required solution is y(x)=1+A\cos x+B\sin x where A and B are constants.

Step-by-step explanation:

Given nonhomogenous differential equation is,

y''(x)+y'(x)=1\hfill (1)   with y_1(x)=1

To find another solution, consider m=\frac{\partial}{\partial x} be such that,

m^2+1=0\implies m=\pm i

Hence,

C.F=A\cos x+B\sin x   where A and B are constants.

Let  D=\frac{\partial}{\partial x}

P.I=\frac{1}{1+D^2}(1)

=(1+D^2)^{-1}(1)

=(1-D^2+.....)(1)=1

Hence,

y(x)=1+A\cos x+B\sin x where A and B are constants.

which is required solution.

6 0
3 years ago
What is the 9th term of the following geometric sequence? 7/9,-7/3,7,-21,63 ??????
dmitriy555 [2]

Given:

The geometric sequence is:

\dfrac{7}{9},\dfrac{-7}{3},7,-21,63,...

To find:

The 9th term of the given geometric sequence.

Solution:

We have,

\dfrac{7}{9},\dfrac{-7}{3},7,-21,63,...

Here, the first term is:

a=\dfrac{7}{9}

The common ratio is:

r=\dfrac{a_2}{a_1}

r=\dfrac{\dfrac{-7}{3}}{\dfrac{7}{9}}

r=\dfrac{-7}{3}\times \dfrac{9}{7}

r=-3

The nth term of a geometric sequence is:

a_n=ar^{n-1}

Where, a is the first term and r is the common ratio.

Substitute a=\dfrac{7}{9},r=-3,n=9 to find the 9th term.

a_9=\dfrac{7}{9}(-3)^{9-1}

a_9=\dfrac{7}{9}(-3)^{8}

a_9=\dfrac{7}{9}(6561)

a_9=5103

Therefore, the 9th term of the given geometric sequence is 5103.

5 0
3 years ago
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