All categories

3 years ago

Triangle whose base is 5.05 and height is 2.4

1 answer:

7 0

The area of a triangle could be calculated by multiplying the half base by the height.

Area = 0.5 * 5.05 * 2.4 = 6.06 square units.

You might be interested in

Are angles AFB and DFC vertical?

Alexxandr [17]

Hi,
I don't think they are because the right angle sign is not there in angle AFB.
Hope this helps you.

7 0

2 years ago

Read 2 more answers

Choose the equation that represents the graph.

sveticcg [70]

Answer:

Answer: Option D

Step-by-step explanation:

Hey there!

From the above question;

The line passes through (-3,0) and (0,3).

Use double point formula;

$( y - y1) = \frac{(y2 - y1)}{(x2 - x1)} (x - x1)$

Keep all values;

$(y - 0) = \frac{(3 - 0)}{(0 - ( - 3))} (x + 3)$

Simplify it;

$y = \frac{3}{3} (x + 3)$

Therefore, y = x+3.

Hope it helps!

4 0

3 years ago

PLEASE HELP I NEED IT TO PASS THIS CLASS

const2013 [10]

Answer:

( a ) 99°

( b ) 151°

Step-by-step explanation:

( a )

( 180 - 81 )° = 99°

( b )

( 180 - 29 )° = 151°

4 0

3 years ago

What is the slope of any line that is perpendicular to the line that contains the points (8,8) and (12,12)

svetlana [45]

Answer: 1

Step-by-step explanation:

12-8=4

4 over 4 is 1

if it perpendicular then it's the opposite reciprocal

hope that help

8 0

2 years ago

How do you do... cos2x-sin2x=1-2sin2x

Bess [88]

$sin (2 \alpha) =2\cdot sin \alpha \cdot cos \alpha \\cos(2 \alpha )=1-2sin^2 \alpha \\-------------------- \\cos2x-sin2x=1-2sin2x\\cos2x+sin2x=1\\1-2sin^2x+2sinx\cdot cosx=1\\-2sinx(sin x-cosx)=0\\ -2sinx=0\ \ \ \ or\ \ \ \ sinx-cosx=0\\\\1)\ -2sinx=0\ \ \Leftrightarrow\ \ sinx=0\ \ \Leftrightarrow\ \ x_1=k \pi \ \ and\ \ k\in I\\2)\ \ sinx-cosx=0\ \ \Leftrightarrow\ \ sinx=cosx\ /:cosx\ \ \ \ \ \wedge\ \ \ \ cos x \neq 0\\tanx=1\ \ \Leftrightarrow\ \ x_2= \frac{ \pi }{4} +k \pi \ \ and\ \ k\in I$

3 0

3 years ago