The only statements that is true about the information on the table are:
- The ratio of students who wish they had flight to those who wish for invisibility -Ratio 2:3. All other statements/ratios are false/incorrect.
<h3>
How do we get the ratio of students who wish they had flight to those who wish for invisibility?</h3>
Ratio is simple math.
The number of people who wish for invisibility are: 12 ; while
The number of people who wish for flight are: 8
Thus the ratio will be given as:
8/12 further simplified by dividing by 4, we have
(8/4) : (12/4)
= 2:3
Hence, only the last statement is true.
Learn more about ratios at:
brainly.com/question/2328454
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Answer:
Step-by-step explanation:
height of pyramid = √(10²-(5/2)²) = √93.75
volume of pyramid = ⅓b²h = ⅓·5²√93.75 ≅ 80.69 in³
lateral area = 2×5×10 = 100 in²
base area = 5² = 25 in²
surface area = 100+25 = 125 in²
Answer:
The answer is C.
Step-by-step explanation:
The answer is C because both numbers in 4:9 can be multiplied by the same factor (3) to get 12:27, the answer. No other choice works because they require two different number factors, not just one, which means they aren't equivalent ratios to 4:9.
Answer:1547.9 miles per hour
Step-by-step explanation:
Let the two trains leave in x direction and y direction
Velocity of train in x direction be v
therefore velocity of train in Y direction is v+29
because one train is 29 miles per hour slower than other.
Distance travel by train in x direction is(x) v(2)
Distance travel by train in y direction is(y) 2(v+29)
distance between them after 2 hours is 4420 miles
Now using pythagoras theorem
on solving
v=
v=1547.889 miles per hour
X^2 + y^2 = (3x^2 + 2y^2 - x)^2
2x + 2y f'(x) = 2(3x^2 + 2y^2 - x)(6x + 4y f'(x) - 1) = 36x^3 + 24x^2yf'(x) + 24xy^2 + 16y^3f'(x) - 4y^2 - 18x^2 - 8xyf'(x) + x
f'(x)(2y - 24x^2y - 16y^3 + 8xy) = 36x^3 + 24xy^2 - 4y^2 - 18x^2 - x
f'(x) = (36x^3 + 24xy^2 - 4y^2 - 18x^2 - x)/(2y - 24x^2y - 16y^3 + 8xy)
f'(0, 0.5) = -4(0.5)^2/(2(0.5) - 16(0.5)^3) = -1/(1 - 2) = -1/-1 = 1
Let the required equation be y = mx + c; where y = 0.5, m = 1, x = 0
0.5 = 1(0) + c = 0 + c
c = 0.5
Therefore, the tangent line at point (0, 0.5) is
y = x + 0.5
