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romanna [79]
3 years ago
14

One evening brody and tessa both had a hot dog. Each hot dog was 2.50. How much was the total

Mathematics
2 answers:
Oksana_A [137]3 years ago
5 0
$5.00
$2.50 + $2.50= $5.00 total amount for hotdogs
bezimeni [28]3 years ago
3 0
$2.50 + $2.50= $5  Two people so two hot dogs            
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A rectangle is constructed with its base on the diameter of a semicircle with radius 2 and with its two other vertices on the se
stealth61 [152]

Answer:

L = 2*√2

w = √2

Step-by-step explanation:

Given:

A rectangle is constructed with its base on the diameter of a semicircle with radius 2 and with its two other vertices on the semicircle.

Find:

What are the dimensions of the rectangle with maximum​ area?

Solution:

- Let the length and width of the rectangle be L and w respectively.

- We know that Length L lie on the diameter base. So , L < 4 and the width w is less than 2 . w < 2.

- Using the Pythagorean Theorem, we relate the L with w using the radius r = 2 of the semicircle.

                           r^2 = (L/2)^2 + (w)^2

                           sqrt (4 - w^2 ) = L / 2

                           L = 2*sqrt (4 - w^2 )           L < 4 , w < 2

- The relation derived above is the constraint equation and the function is Area A which is function of both L and w as follows:

                          A ( L , w ) = L*w

- We substitute the constraint into our function A:

                          A ( w ) = 2*w*sqrt (4 - w^2 )

- Now we will find the critical points for width w for which A'(w) = 0

                         A'(w) = 2*sqrt (4 - w^2 ) - 2*w^2 / sqrt (4 - w^2 )  

                         0 = [2*sqrt (4 - w^2 )*sqrt (4 - w^2 )   - 2*w^2] / sqrt (4 - w^2 )  

                         0 = 2*(4 - w^2 )   - 2*w^2

                         0 = -4*w^2 + 8

                         8/4 = w^2

                         w = + sqrt ( 2 )   ..... 0 < w < 2

- From constraint equation we have:

                          L = 2*sqrt (4 - 2 )

                          L = 2*sqrt(2)

7 0
4 years ago
57846*3746 help please
Mars2501 [29]

Answer:216691116

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What is the relationship between the 6s in the number 660,472
Bess [88]
The 6 in the hundred thousands place in tens times greater than the 6 in the ten hundreds place
7 0
3 years ago
(V+5)(-1/9)=6 how do u solve this
Brrunno [24]

Answer:

v= -59

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : (v+5)*(-1/9)-(6)=0

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    (v+5)*(-1/9)-(6)=0

Step by step solution :

STEP

1

:

           1

Simplify   —

           9

Equation at the end of step

1

:

                  1      

 ((v + 5) • (0 -  —)) -  6  = 0

                  9      

STEP

2

:

Equation at the end of step 2

 (-v - 5)    

 ———————— -  6  = 0

    9        

STEP

3

:

Rewriting the whole as an Equivalent Fraction

3.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  9  as the denominator :

        6     6 • 9

   6 =  —  =  —————

        1       9  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

STEP

4

:

Pulling out like terms

4.1     Pull out like factors :

  -v - 5  =   -1 • (v + 5)

Adding fractions that have a common denominator :

4.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

(-v-5) - (6 • 9)     -v - 59

————————————————  =  ———————

       9                9  

STEP

5

:

Pulling out like terms :

5.1     Pull out like factors :

  -v - 59  =   -1 • (v + 59)

Equation at the end of step

5

:

 -v - 59

 ———————  = 0

    9  

STEP

6

:

When a fraction equals zero :

6.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 -v-59

 ————— • 9 = 0 • 9

   9  

Now, on the left hand side, the  9  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  -v-59  = 0

Solving a Single Variable Equation:

6.2      Solve  :    -v-59 = 0

Add  59  to both sides of the equation :

                     -v = 59

Multiply both sides of the equation by (-1) :  v = -59

5 0
3 years ago
I made a fort by two boxes. The first box is 4 meters long, 8 meters wide, and 8 meters high. The second box is 2 meters long, 7
ArbitrLikvidat [17]

Answer:

242 m³ of space is there in the fort.

Step-by-step explanation:

Given that,

The dimensions of first box is 4 meters long, 8 meters wide, and 8 meters high.

The dimensions of the second box is 2 meters long, 7 meters wide, and 1 meter high.

Space left = Volume of first box - volume of second box

= (4)(8)(8) - 2(7)(1)

= 242 m³

So, 242 m³ of space is there in the fort.

7 0
3 years ago
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