The length of a rectangular poster is 7 inches more than twice its width. Find the length of the poster if its perimeter is 110 inches.
1 answer:
Let W = width of poster Since the length is 7 inches longer than the width, the length is represented by W + 7. We know the perimeter is equal to twice the length + twice the width and that is 110 inches. Mathematically that looks like: 2(W + 7) + 2(W) = 110 Now let's solve for W: 2(w+7)+2w=110 Step 1: Simplify both sides of the equation. 2(w+7)+2w=110 Simplify: (see simplify steps down below) 4w+14=110 Step 2: Subtract 14 from both sides. 4w+14−14=110−14 4w=96 Step 3: Divide both sides by 4. 4w4=964 w=24 Answer: w=24 Simplify Steps: (2)(w)+(2)(7)+2w=110(Distribute) 2w+14+2w=110 (2w+2w)+(14)=110(Combine Like Terms) 4w+14=110
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