Answer:
Between 38.42 and 49.1.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
Approximately 68% of the measures are within 1 standard deviation of the mean.
Approximately 95% of the measures are within 2 standard deviations of the mean.
Approximately 99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean of 43.76, standard deviation of 2.67.
Between what two values will approximately 95% of the amounts be?
By the Empirical Rule, within 2 standard deviations of the mean. So
43.76 - 2*2.67 = 38.42
43.76 + 2*2.67 = 49.1
Between 38.42 and 49.1.
Answer:
4.8 pounds!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
It must be ≤ instead of ≥.
y ≤ - 3·x + 4
Answer:
Fraction of fire trucks = 
Total number of toy cars = 
Step-by-step explanation:
Fraction of sports car = 
Fraction of remaining cars 
So,
Fraction of pick up cars = 
Therefore,
Fraction of fire trucks = 
That is Number of fire trucks = ( Total number of toy cars )
Number of fire trucks = 4
Total number of toy cars = 
Answer:
The player with the most runs had a rush of 1,240 yards
Step-by-step explanation:
In this question, we are asked to calculate the number of yards that was rushed by one of two person given their combined run and an extra information.
Firstly, let the person that had the smaller number of rush have a rush of x rushes. The second person has a rush of 4 times the other. This makes a number of 4x rushes
By adding both together, we have a total of 1550 yards
Mathematically, this means that x + 4x = 1550
5x = 1550
x = 1550/5 = 310 rushes
The second player had a rush of 4x and that is 4 * 310 = 1,240 rushes
