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Inga [223]
4 years ago
5

How to I work out the answer?

Mathematics
1 answer:
nasty-shy [4]4 years ago
4 0
1gcm-³ = 1000kgm-³
so 2.7gcm-³ = 2700kgm-³ (density)
volume = 1×0.6×0.3m³ = 0.18m³

mass = density ×volume = 2700×0.18 Kg = 486Kg
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What is 3√25 - √9 expressed in simplified form?<br> 12<br> 15<br> 66<br> 72
tigry1 [53]
A number outside of the square root symbol is actually multiplied by the square root of the number under the symbol. 25 and 9 are considered perfect squares because a number multiplied by itself goes evenly into each without any remainders.

=3√25 - √9
take the square root of 25 and 9

=3(5) - 3
multiply 3*5

=15 - 3
=12


ANSWER: 12 (first choice)

Hope this helps! :)
7 0
3 years ago
7x+14-2(x+4) how to solve it
sergejj [24]

Answer:

x= -(6/5)

Step-by-step explanation:

if what ur saying = 0

7x+14-2(x+4)

distribute the -2

7x+14-2x-8

7x-2x

14-8

5x+6=0

-6        -6

5x=-6

/5     /5

x= -(6/5)

6 0
4 years ago
Read 2 more answers
I need help please with this problem
vredina [299]
30:60:90 is 3:6:9 in ratio form
5 0
3 years ago
Help, &gt; &lt; or =?<br><br><br> |-6| ? 4
Damm [24]

Answer:

>

Step-by-step explanation:

Because |-6| = 6

and 6 is greater than 4

8 0
3 years ago
If a polynomial function f(x) has roots –8, 1, and 6i, what must also be a root of f(x)? A. –6
anyanavicka [17]

Answer:

-6i

Step-by-step explanation:

Complex roots always come in pairs, and those pairs are made up of a positive and a negative version. If 6i is a root, then its negative value, -6i, is also a root.

If you want to know the reasoning, it's along these lines: to even get a complex/imaginary root, we take the square root of a negative value. When you take the square root of any value, your answer is always "plus or minus" whatever the value is. The same thing holds for complex roots. In this case, the polynomial function likely factored to f(x) = (x+8)(x-1)(x^2+36). To solve that equation, you set every factor equal to zero and solve for the x's.

x + 8 = 0

x = -8

x - 1 = 0

x = 1

x^2 + 36 = 0

x^2 = -36 ... take the square root of both sides to get x alone

x = √-36 ... square root of an imaginary number produces the usual square root and an "i"

x = ±6i

6 0
3 years ago
Read 2 more answers
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