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3 years ago

Please helpp. I have to get this done before 10:05.

Mathematics

1 answer:

Svetllana [295]3 years ago

5 0

Answer:Adjacent angles are two angles that have a common vertex and a common side but do not overlap. In the figure, ∠1 and ∠2 are adjacent angles.

Step-by-step explanation:

It is correct

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3 years ago

SOMEONE PLEASE JUST ANSWER THIS FOR BRAINLIEST!!!

Sloan [31]

ANSWER

$P-G = 11{w}^{4} - 5 {w}^{2} {z}^{2} - 4z^{4}$

EXPLANATION

The given polynomials are:

$G = - 3 {w}^{4} + 2 {w}^{2} {z}^{2} + 5z^{4}$

and

$P = 8 {w}^{4} - 3{w}^{2} {z}^{2} + z^{4}$

We want to subtract these two polynomials.

$P-G = 8 {w}^{4} - 3{w}^{2} {z}^{2} + z^{4} - (- 3 {w}^{4} + 2 {w}^{2} {z}^{2} + 5z^{4} )$

Expand the right hand side to obtain:

$P-G = 8 {w}^{4} - 3{w}^{2} {z}^{2} + z^{4} + 3 {w}^{4} - 2 {w}^{2} {z}^{2} - 5z^{4}$

Group the similar terms:

$P-G = 8 {w}^{4} + 3 {w}^{4}- 3{w}^{2} {z}^{2} - 2 {w}^{2} {z}^{2} - 5z^{4} + z^{4}$

Combine the similar terms to get:

$P-G = 11{w}^{4} - 5 {w}^{2} {z}^{2} - 4z^{4}$

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3 years ago

Find x<br> 5[x^2]+5[x]-x^2-x=2004

a_sh-v [17]

The answer is either $x=\frac{-1}{2}+\frac{1}{2}\sqrt{2005}\\$ or $x=\frac{-1}{2}+\frac{-1}{2}\sqrt{2005}$

To solve: Let's solve your equation step-by-step.

5x2+5x−x2−x=2004

Step 1: Simplify both sides of the equation.

4x2+4x=2004

Step 2: Subtract 2004 from both sides.

4x2+4x−2004=2004−2004

4x2+4x−2004=0

Step 3: Use quadratic formula with a=4, b=4, c=-2004.

x= −b±√b2−4ac /2a

x= −4±√32080 /8

$x=\frac{-1}{2}+\frac{1}{2}\sqrt{2005}\\$ or $x=\frac{-1}{2}+\frac{-1}{2}\sqrt{2005}$

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3 years ago

Read 2 more answers