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3 years ago

A circle has an area of 30 in^2. What is the area of a 60 sector of this circle?

Mathematics

1 answer:

yuradex [85]3 years ago

5 0

We use the ratio x:360 to find portions of the circle (again, through the ratio)

so we use 60/360 = x/30 in^2

1/6 = x/ 30

x = 5.

The answer is 5 in^2

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In a school, only 13 out of 15 student participate in a competition.what is the probability of the student who do not makes it t

Papessa [141]

Answer:

$\frac{2}{15}$

Step-by-step explanation:

Number of students participating in the competition = 13.

Total number of students in the school = 15.

Thus ,

the number of students who did not make to this competition =

Total number of students - number of students participated

= 15-13 = 2.

Now ,

probability of the student who do not makes it to the competition

= fraction of students who did not make to this competition from the total number of students .

= $\frac{2}{15}$ .

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3 years ago

What is an equation of the line that passes through the points (−2,8) and (1,−1)

dem82 [27]

Answer:

y = -3x + 2

Explanation:

Do the rise over run equation to find slope

Slope = 3

Plug in slope to equation and also choose one of the coordinate points to plug in x and y so you can find b

Plug in all of this to get final y=mx+b form

3 0

3 years ago

Tara runs an amusement park ride and needs to count the people who get on the ride. At the beginning of her shift, 132 people ha

DanielleElmas [232]

Y= the number riders over time
x= hours into Tara's shift
y= 33x + 132

6 0

3 years ago

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A construction company built a scale model of a building. The model was built using a scale of 3 inches = 32 feet. If the buildi

Vlad1618 [11]

Let x represent the height of the model.

We have been given that a construction company built a scale model of a building. The model was built using a scale of 3 inches = 32 feet. We are asked to find the height of the model, if the building is expected to be 200 feet tall.

We will use proportions to solve our given problem as:

$\frac{\text{Model height}}{\text{Actual height}}=\frac{\text{Model length}}{\text{Actual length}}$

Upon substituting our given values, we will get:

$\frac{x}{200\text{ ft}}=\frac{3\text{ in}}{\text{32 ft}}$

$\frac{x}{200\text{ ft}}\times 200\text{ ft}=\frac{3\text{ in}}{\text{32 ft}}\times 200\text{ ft}$

$x=3\text{ in}\times 6.25$

$x=18.75\text{ in}$

Therefore, the model will be 18.75 inches tall.

7 0

3 years ago

Please help and thank you

tatiyna

Answer:

$b_{1}=\frac{2A}{h}-b_{2}$

Step-by-step explanation:

Given: $A=\frac{1}{2}(b_{1} +b_{2})h$

We need to completely isolate $b_{1}$ to solve.

$A=\frac{1}{2}(b_{1} +b_{2})h$

$A=(\frac{1}{2}b_{1} +\frac{1}{2} b_{2})h$

$A=\frac{1}{2}b_{1} h+\frac{1}{2}b_{2}h$

$-\frac{1}{2}b_{1}h+A=\frac{1}{2}b_{2}h$

$-\frac{1}{2}b_{1}h=-A+\frac{1}{2}b_{2}h$

$-\frac{1}{2}b_{1}=\frac{-A}{h}+\frac{1}{2}b_{2}$

Finally, multiply both sides by -2 to completely isolate $b_{1}$ .

$b_{1}=\frac{2A}{h}-b_{2}$

5 0

3 years ago

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