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postnew [5]
3 years ago
11

A circle has an area of 30 in^2. What is the area of a 60 sector of this circle?

Mathematics
1 answer:
yuradex [85]3 years ago
5 0

We use the ratio x:360 to find portions of the circle (again, through the ratio)

so we use 60/360 = x/30 in^2

1/6 = x/ 30

x = 5.

The answer is 5 in^2

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HELP PLSSS THIS IS HARD SOMEONE
Oduvanchick [21]

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Explain why each table determine if y is proportional to x .
lesya692 [45]

Answer:

see explanation

Step-by-step explanation:

If y is proportional to x then the equation relating them is

y = kx ← k is the constant of proportion

To find k divide both sides by x

k = \frac{y}{x}

This value must be constant for all ordered pairs, thus

k = \frac{4}{6} = \frac{2}{3}

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Combine the following expressions:
melisa1 [442]

ANSWER

(4n - 1)\sqrt{3 n} + 3\sqrt{n}

EXPLANATION

The given expression is

\sqrt{48 {n}^{3} }  +  \sqrt{9n}  -  \sqrt{3n}

We remove the perfect squares under the radical sign.

\sqrt{16 {n}^{2}  \times3 n}  +  \sqrt{9n}  -  \sqrt{3n}

We can now take square root of the perfect squares and simplify them further.

\sqrt{16 {n}^{2}}   \times \sqrt{3 n} +   \sqrt{9} \times  \sqrt{n}  -  \sqrt{3n}

This simplifies to:

4n\sqrt{3 n} + 3\sqrt{n}  -  \sqrt{3n}

This further simplifies to:

(4n - 1)\sqrt{3 n} + 3\sqrt{n}

3 0
2 years ago
Read 2 more answers
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