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Helen [10]
3 years ago
9

Quadrilateral H’ is the image of quadrilateral H after a sequence of transformations. If quadrilateral H’ is congruent to quadri

lateral H, which transformations could have been used ?
A dilation by a scale factor of 2 followed by a reflection
A rotation followed by a dilation by a scale factor of 1/2
A reflection,a translation of 1 unit left, and then a dilation by a scale factor of 3
A translation of 6 units down a rotation and then a reflection
Mathematics
2 answers:
Nataly_w [17]3 years ago
8 0
The last one is correct



A translation of 6 units down a rotation and then a reflection






good luck
Klio2033 [76]3 years ago
7 0

Answer: A translation of 6 units down a rotation and then a reflection

Step-by-step explanation:

  • The rigid transformations preserves the side length and angle measure of a figure such that figure doesn't shrink or get enlarger. It creates congruent figures.
  • There are four rigid transformations such as :

a) reflections, b) rotations, c) translations and d) glide reflection.

  • A dilation changes the size of the image when the scale factor is not equal to 1. It does not creates congruent images.

Hence, if quadrilateral H’ is congruent to quadrilateral H, then the transformation must be :

A translation of 6 units down a rotation and then a reflection.

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Given: sin(18m-12)=cos(7m+2), find the value of m.
V125BC [204]

Answer:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or m = 2/3 - (π n_2)/18 for n_2 element Z

Step-by-step explanation:

Solve for m:

-cos(7 m + 2) sin(12 - 18 m) = 0

Multiply both sides by -1:

cos(7 m + 2) sin(12 - 18 m) = 0

Split into two equations:

cos(7 m + 2) = 0 or sin(12 - 18 m) = 0

Take the inverse cosine of both sides:

7 m + 2 = π n_1 + π/2 for n_1 element Z

or sin(12 - 18 m) = 0

Subtract 2 from both sides:

7 m = -2 + π/2 + π n_1 for n_1 element Z

or sin(12 - 18 m) = 0

Divide both sides by 7:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or sin(12 - 18 m) = 0

Take the inverse sine of both sides:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or 12 - 18 m = π n_2 for n_2 element Z

Subtract 12 from both sides:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or -18 m = π n_2 - 12 for n_2 element Z

Divide both sides by -18:

Answer: m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or m = 2/3 - (π n_2)/18 for n_2 element Z

3 0
3 years ago
The product of g and 4
ikadub [295]

Answer:

4 grams............

Step-by-step explanation:

4 0
3 years ago
It has taken me 32 minutes to drive 48 km. If the total length of my journey is 146 km and I
pentagon [3]
Answer: 1h and 25min

To find how long you can drive in a minute we do 48 divided by 32 = 1.5. So it takes 1 min to drive 1.5km

Then we 146 divided by 1.5 = 97 and a third to find out how long it takes to drive 146km.

Then we convert it to hours to get 1h and 57min.

Then we - 32 because we already drove 32min. 1h and 57min - 32 = 1h and 25min
6 0
2 years ago
What is the correct first step to solve this system of equations by elimination?
storchak [24]

\bold{\huge{\pink{\underline{ Solution }}}}

\bold{\underline{ Given }}

  • <u>We </u><u>have </u><u>given </u><u>two </u><u>linear </u><u>equations </u><u>that</u><u> </u><u>is </u><u>2x </u><u>-</u><u> </u><u>3y </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>and </u><u>x</u><u> </u><u>+</u><u> </u><u>3y </u><u>=</u><u> </u><u>1</u><u>2</u><u> </u><u>.</u>

\bold{\underline{ To \: Find }}

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>x </u><u>and </u><u>y </u><u>by </u><u>elimination </u><u>method</u><u>. </u>

\bold{\underline{ Let's \: Begin }}

\sf{ 2x - 3y = -6 ...eq(1)}

\sf{ x +  3y = 12 ...eq(2)}

<u>Multiply </u><u>eq(</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>by </u><u>2</u><u> </u><u>:</u><u>-</u>

\sf{ 2( x + 3y = 12 )}

\sf{ 2x + 6y = 24 }

<u>Subtract </u><u>eq(</u><u>1</u><u>)</u><u> </u><u>from </u><u>eq(</u><u>2</u><u>)</u><u> </u><u>:</u><u>-</u>

\sf{ 2x + 6y -( 2x - 3y) = 24 -(-6)}

\sf{ 2x + 6y - 2x + 3y = 24 + 6 }

\sf{   9y = 30 }

\sf{   y = 30/9}

\sf{\red{ y = 10/3}}

<u>Now</u><u>, </u><u> </u><u>Subsitute</u><u> </u><u>the </u><u>value </u><u>of </u><u>y </u><u>in </u><u>eq(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u><u>-</u>

\sf{ 2x - 3(10/3) = -6 }

\sf{ 2x - 10 = -6 }

\sf{ 2x  = -6 + 10}

\sf{ x  = 4/2}

\sf{\red{ x  = 2}}

Hence, The value of x and y is 2 and 10/3

6 0
2 years ago
Pls help thx , I’m behind ;(
sweet-ann [11.9K]
5 is the in its value bc its on the y intercept meaning the starting point
6 0
2 years ago
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