Let C(x) = -0.75x + 20,000 and R(x)= -1.50x then the profit function exists noted as P(x) = R(x) - C(x)
P(x) = -1.50x - (-0.75)x + 20,000
P(x) = -0.75x + 20000
Therefore, the profit function exists -0.75x + 20000.
<h3>How to find profit function?</h3>
The profit function can be estimated by subtracting the cost function from the revenue function. Let profit be expressed as P(x), the revenue as R(x), the cost as C(x), and x as the number of items traded. Then the profit function exists noted as P(x) = R(x) - C(x).
Given:
C(x) = -0.75x+20,000 and R(x)= -1.50x
P(x) = R(x) - C(x)
= -1.50x - (-0.75)x + 20,000
= -1.50x + 0.75x + 20,000
Apply rule -(-a) = a
= -1.5x + 0.75x + 20000
Add similar elements:
-1.5 x + 0.75x = -0.75x
P(x) = -0.75x + 20000
Therefore, the profit function exists -0.75x + 20000.
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Answer:
Each fraction is greater than the previous fraction.
Explanation:
The bigger the denominator, the smaller the fraction.
Answer:
Distance between the points Q and R is 1 unit while the distance between the points R and S is 3 units
Step-by-step explanation:
Here, we want to use the absolute value of the coordinates to find the distances.
Since we are using absolute values, the negative points becomes positive;
Thus;
Q = (4,2)
R = (3,2)
S = (3,5)
Mathematically, the distance between two points in the Cartesian plane can be calculated using the formula;
D = √(x2-x1)^2 + (y2-y1)^2
The distance QR is thus;
D = √(3-4)^2 + (2-2)^2
D = √(-1)^2 + 0
D = √1 = 1 unit
The distance RS is thus;
D = √(3-3)^2 + (5-2)^2
D = √(0) + (9)
D = √9 = 3 units
Multiply 40 and 6 and then add the remainder (16):
240+16 = 256
check by dividing "the number," 256, by 40. Is the partial quotient 6? Is there a remainder of 16? YES and YES.
